This is the Grade 9 Science self-learning module for Quarter 2 (Matter), Module 7: The Mole Concept. It is written for Grade 9 learners studying at home, with support from parents and teachers. After working through it, learners should be able to use the mole to connect the mass of a substance, its number of moles, and its number of particles.
The module was developed by the Department of Education National Capital Region as part of its Alternative Delivery Mode (First Edition, 2020). It has one lesson, Lesson 1: The Mole Concept.
On this page 6 sections
What learners will learn
The module targets this learning competency:
- Use the mole concept to express mass of substances. (S9MT-IIi-19)
After going through the module, learners are expected to:
- differentiate molecular unit from formula unit and compute for the molecular mass;
- define mole and calculate the number of moles of given compounds;
- compute the number of particles given the mass or number of moles; and
- convert number of moles, mass, and number of particles from one unknown to another.
Key ideas in the lesson
Counting units and the mole
The lesson opens with a game show puzzle: how do you estimate the number of mongo seeds in a container without counting them one by one? You can count a small number, weigh them, and work out the ratio. Atoms are much harder, because they are too small to count or weigh one at a time.
So chemists use a counting unit, just as we use a pair (2) for slippers or a dozen (12) for eggs. That unit is the mole (mol). One mole of any substance contains 6.02 x 10²³ particles. This value is called Avogadro’s number, named after the Italian scientist Amedeo Avogadro. It is the number of atoms in 12 grams of carbon-12.
The module’s examples:
- 1 mole of table salt (NaCl) = 6.02 x 10²³ NaCl ion pairs
- 1 mole of gold (Au) = 6.02 x 10²³ Au atoms
- 1 mole of sugar (C12H22O11) = 6.02 x 10²³ sugar molecules
- 1 mole of water (H2O) = 6.02 x 10²³ H2O molecules
The calculations that relate mass, moles, and particles are part of stoichiometry.
Formula mass and molecular mass
The module compares the two values this way:
| Formula mass | Molecular mass |
|---|---|
| Uses amu (atomic mass unit) | Uses g/mol (gram per mole) |
| Calculated from the empirical formula | Calculated from the molecular formula |
| Used for ionic compounds | Used for covalent compounds |
Both are calculated in three steps:
- Count the atoms of each element in the formula.
- Find each element’s atomic mass on the periodic table and multiply it by the number of atoms.
- Add all the products.
Worked examples in the module:
- Mefenamic acid, C13H18O2: (13 x 12.01) + (18 x 1.01) + (2 x 16.00) = 206.31 amu
- Limewater, Ca(OH)2: 40.08 + (2 x 1.01) + (2 x 16.00) = 74.10 amu
Converting between mass, moles, and particles
The module uses dimensional analysis for these conversions:
| What you know | What you want | How to solve |
|---|---|---|
| Number of moles | Mass | moles x molar mass (g/mol) |
| Mass | Number of moles | mass x (1 mol / molar mass in g) |
| Number of moles | Number of particles | moles x 6.02 x 10²³ |
Sample problems from the module:
- Moles of O2 in 24.0 g: 24.0 g x (1 mol / 32.0 g) = 0.75 mol
- Mass of 2 moles of magnesium: 2 mol x 24 g/mol = 48 g
- Moles in 36 g of water (molar mass 18 g/mol): 36 g x (1 mol / 18 g) = 2 mol
- Molecules in 3 moles of CO2: 3 x 6.02 x 10²³ = 1.806 x 10²⁴ molecules
The big idea is that one mole of different substances always has the same number of particles, but different masses.
Activities in this module
- What I Know: a 10-item pretest
- What’s In: a review of hydrocarbons (alkanes, alkenes, alkynes) from the previous module
- What’s New: a counting-units table (pair, dozen, and more)
- What’s More: five activities on molecular mass, a code puzzle on mole and mass problems, a laboratory label table, particle conversions, and a mass-mole-particle comparison
- What I Have Learned: a 10-item fill-in-the-blank review
- What I Can Do: finding the molecular mass, moles, and particles in 100 grams of ammonium phosphate fertilizer
- Assessment: a 10-item post-test
- Additional Activities: counting sunflower seeds, strawberries, and rice grains in moles
How to use this module
- Learners: Start with the pretest to see what you already know. Then work through the parts in order. Write all answers on a separate sheet of paper, not on the module. Take the assessment at the end, and use the answer key honestly to check your work. Keep a periodic table nearby for atomic masses.
- Parents: Help your child follow the steps in the worked examples and check that each answer includes its unit (g, mol, or particles). Contact the teacher if your child gets stuck.
- Teachers: The answer key is at the back of the module. Some entries do not match the lesson’s own content, so check them before you use the key for checking or grading.
Frequently asked questions
What grade and quarter is The Mole Concept module for?
It is Grade 9 Science, Quarter 2 (Matter), Module 7.
What is a mole in chemistry?
A mole is the amount of a substance that contains 6.02 x 10²³ particles, the same number of atoms found in 12 grams of carbon-12. This value is called Avogadro’s number.
How do you convert mass to moles?
Multiply the mass in grams by 1 mole over the molar mass. For example, 36 g of water x (1 mol / 18 g) = 2 mol.
What is the competency code of this module?
The module targets S9MT-IIi-19: use the mole concept to express mass of substances.
Does the module have an answer key?
Yes. Answer keys for the pretest, activities, and assessment are at the back of the module, although a few entries should be double-checked.
Full text of the module
The text below is a transcription of the PDF above, as printed.
Science Quarter 2- Matter Module 7: The Mole Concept
Science Quarter 2- Matter Module 7: The Mole Concept
[illustration: students of different ages studying, reading, and writing outdoors and at home, with a teacher, a globe, and a lamp]
CO_Q2_Science 9_ Module 7
Science – Grade 9 Alternative Delivery Mode Quarter 2: Matter – Module 7: The Mole Concept First Edition, 2020
Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties.
Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them.
Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio
Development Team of the Module
Writer: Ramil A. Bautista Editor: Loreta E. Santos Reviewers: Aurora T. Alcazar, Anthony D. Angeles, Lonida A. Caiña, Mary Grace C. Dimacutac, Mary Grace G. Fuentes, Myla D. German, Myrla D. Guevarra, Heddy C. Portuguese, Rosemarie V. Rodanilla, Avie John Tesorero Language: Elvira P. Emerenciana, Nova V. Tarcena, Lilibeth M. De Lansig Design and Layout: Edgardo Q. Reyes Layout Artist: Ramil A. Bautista, Mark Joseph Y. Samarita, Ana Lisa M. Mesina Management Team: Malcolm S. Garma, Genia V. Santos, Dennis M. Mendoza, Micah S. Pacheco, Josefina M. Pablo, Manolo C. Davantes Jr., Dalisay E. Esguerra, Hilda C. Valencia
Printed in the Philippines by _____
Department of Education – National Capital Region
Office Address: Misamis St. Bago Bantay, Quezon City Telefax: (632)8929-0153 E-mail Address: depedncr@deped.gov.ph
9
Science Quarter 2- Matter Module 7: The Mole Concept
Introductory Message
This Self-Learning Module (SLM) is prepared so that you, our dear learners, can continue your studies and learn while at home. Activities, questions, directions, exercises, and discussions are carefully stated for you to understand each lesson.
Each SLM is composed of different parts. Each part shall guide you step-by-step as you discover and understand the lesson prepared for you.
Pre-tests are provided to measure your prior knowledge on lessons in each SLM. This will tell you if you need to proceed on completing this module or if you need to ask your facilitator or your teacher’s assistance for better understanding of the lesson. At the end of each module, you need to answer the post-test to self-check your learning. Answer keys are provided for each activity and test. We trust that you will be honest in using these.
In addition to the material in the main text, Notes to the Teacher are also provided to our facilitators and parents for strategies and reminders on how they can best help you on your home-based learning.
Please use this module with care. Do not put unnecessary marks on any part of this SLM. Use a separate sheet of paper in answering the exercises and tests. And read the instructions carefully before performing each task.
If you have any questions in using this SLM or any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator.
Thank you.
What I Need to Know
This module is designed and written with you in mind. It is here to help you master The Mole Concept. The scope of this module permits it to be used in many different learning situations. The language used recognizes the diverse vocabulary level of students. The lessons are arranged to follow the standard sequence of the course, but the order in which you read them can be changed to correspond with the textbook you are now using.
The module focuses on achieving this learning competency:
Use the mole concept to express mass of substances. (S9MT-IIi-19)
After going through this module, you are expected to:
- differentiate molecular unit from formula unit and compute for the molecular mass;
- define mole and calculate for the number of moles of given compounds;
- compute for the number of particles given the mass or number of moles; and,
- convert number of moles, mass, and number of particles from one unknown to another.
What I Know
Choose the letter of the best answer. Write your answer on a separate sheet of paper.
Which is the correct formula unit for sodium chloride?
- A. NaCl
- B. Na₂Cl
- C. Na₃Cl₂
- D. Na₂Cl₅
Caffeine is a natural compound commonly found in coffee, tea, chocolate, and softdrinks. What is the molar mass of caffeine (C₈H₁₀N₄O₂)?
- A. 171.1 g/mol
- B. 189.4 g/mol
- C. 194.2 g/mol
- D. 199.8 g/mol
The pain reliever mefenamic acid contains an active ingredient called Ibuprofen C₁₃H₁₈O₂. What is the molecular mass for this compound?
- A. 200.1 g/mol
- B. 206.3 g/mol
- C. 222.3 g/mol
- D. 240.54 g/mol
Amedeo Avogadro is an Italian scientist who used a constant number to represent the mole of a substance. Which of these represents the number of units in one mole of any substance?
- A. 3.01 x 10²³
- B. 3.01 x 10²⁴
- C. 6.02 x 10²³
- D. 6.02 x 10²⁴
Which represents a mole?
- A. 6 g of NaCl
- B. 3.01 x 10²³ CH₄ molecules
- C. 6.02 x 10²³ F atoms
- D. 25 g graphite, C-atom
How is molar mass of a substance calculated?
- A. Atomic mass of an element minus the number of atoms as indicated by chemical formula.
- B. Number of atoms as indicated by chemical formula divided by atomic weight.
- C. Atomic mass of an element multiplied by the number of each atom of each element as indicated by chemical formula then add all the products of all the elements.
- D. Number of atoms as indicated by chemical formula divided by atomic mass of an element.
If one mole of Aluminum weighs 26.98 grams, what is the mass in grams of 4.30 moles of Aluminum?
- A. 22.68 g Al
- B. 6.27 g Al
- C. 27.28 g Al
- D. 116 g Al
Which is the correct way of converting moles to mass?
- A. number of moles multiplied by molar mass
- B. number of moles divided by the molar mass
- C. number of moles divided by the Avogadro’s number
- D. number of moles multiplied by Avogadro’s number
How many moles are contained in 34g of NH₃?
- A. 1 mol
- B. 2 mol
- C. 17 mol
- D. 34 mol
What is the mass of 4.39 mol Na?
- A. 191 g
- B. 252 g
- C. 120 g
- D. 101 g
Lesson 1 The Mole Concept
In this module you will be able to: differentiate molecular unit from formula unit and compute for the molecular mass; define mole and calculate for the number of moles of given compounds; compute for the number of particles given the mass or number of moles; and, convert number of moles, mass, and number of particles from one unknown to another.
For example, a game show requires the contestants to guess the number of mongo seeds in a container. The player who guesses closest amount to the actual number of seeds will win the grand prize. How would they estimate the number of seeds without counting it one by one?
One way to get the easiest estimation is to count 10 seed or more, then weigh them and find their ratio. This is similar in counting the number of atoms in a substance, but it is more difficult because atoms cannot be counted nor weighed individually.
In this module, you will learn how to express the mass of substance using the basic concept of mole.
Here are some key questions for you to ponder after finishing this module:
- What is a mole?
- What is the difference between molecular and formula unit?
- What is the relationship of the mole to mass and number of particles of a compound or element?
- How to calculate the number of particles (atoms, molecules, ions) from moles or vice versa?
- What are the steps in converting number of moles to mass or vice versa?
What’s In
In the previous module, you have learned the different kinds of hydrocarbons and their uses. Look at the structural diagram of hydrocarbons below and answer the following questions.
[chart: structural diagrams of hydrocarbons; three labeled structures (a), (b), (c)]
(a) (b) (c)
[transcriber’s note: the drawings in (a) and (b) show full hydrogen-carbon structures that are not reproduced here; the printed bond in (c) is H–C≡C–H]
Guide Questions:
- Which of these sets of hydrocarbons is alkane?
- Which of these are alkene and alkynes?
- How will you describe the bond between b and c?
- What elements are mostly present in all the three given compounds?
What’s New
The counting units are often used to easily represent the number of items. It is more convenient to represent this as collective counting words than counting them individually. Atoms are incredibly small. It is impossible to count the number of atoms or molecules to get their mass. Using counting units, we can easily represent the number of atoms. Complete the needed information in the third column.
| Items | Counting Units | Number of Pieces |
|---|---|---|
| Slippers [photo: pair of slippers] | Pair | 2 |
| Eggs [photo: eggs in a carton] | Dozen |
CO_Q2_Science 9_ Module 7
What is It
Molecular and Formula Mass
Let us differentiate molecular mass from formula mass. The formula mass and molecular mass are two values that express the size of a molecule. The formula mass of a molecule is the sum average of the atomic weights of the atoms in its empirical formula.
However, the molecular mass of a molecule is its average mass as calculated by adding the atomic weights of the atoms in the molecular formula.
The table shows the difference between formula and molecular mass:
| Formula mass | Molecular mass |
|---|---|
| Use amu (atomic mass unit) as units. | Use g/mol (gram per mole) as units. |
| Mass of molecules may not be exact. | Always give the exact mass of a mole of molecules |
| Calculated through empirical formula | Calculated through molecular formula |
| Sum of the masses of atoms present in the empirical formula. | Mass of a mole of a given molecule. |
| Used for ionic compounds | Used for covalent bond compounds |
Let us analyze the given samples using the following steps to calculate molecular mass of a substance.
Steps in Calculating Molecular Mass
1st step: Determine the number of atoms of the elements present in the molecule.
2nd step: Find the atomic mass of each atom using the periodic table of elements. Multiply the atomic mass to the number of atoms of the elements present in the molecule.
3rd step: Get the sum of all the product.
Sample 1: Mefenamic acid consist of C13H18O2, a common compound that is mostly used in pain medication. What is the molecular mass for this compound?
| Element | Quantity | Average atomic mass (amu) | Subtotal (amu) |
|---|---|---|---|
| C | 13 X | 12.01 = | 156.13 |
| H | 18 X | 1.01 = | 18.18 |
| O | 2 X | 16.00 = | 32.00 |
| Molecular Mass | 206.31 |
The molecular mass of mefenamic acid (C13H18O2) is 206.31 amu
Steps in Calculating Formula Mass
1st step: Determine the number of atoms of the elements present in the molecule.
2nd step: Find the atomic mass of each atom using the periodic table of elements. Multiply the atomic mass to the number of atoms of the elements present in the molecule.
3rd step: Get the sum of all the product.
Sample 2: Compute the formula mass of limewater, Ca(OH)2
| Element | Quantity | Average atomic mass (amu) | Subtotal (amu) |
|---|---|---|---|
| Ca | 1 X | 40.08 = | 40.08 |
| H | 2 X | 1.01 = | 2.02 |
| O | 2 X | 16.00 = | 32.00 |
| Formula Mass | 74.10 |
The formula mass of limewater, Ca(OH)2 74.10 amu.
What is Mole?
We use counting units to easily represent the quantity of materials. Just as we denote 1 dozen for 12 eggs, it can be 1 dozen for 12 bananas or 12 candies. Similarly, a mole is used to count entities on a microscopic level like atoms, molecules, ions, particles etc.
In Chemistry, mole (mol) is simply defined as the quantity of a substance which contains the same number of particles. Look at the illustration below to understand how the mole expresses quantity and unit based on number.
[photo: a dish of table salt] 1 mole of table salt (NaCl) = 6.02 x 10²³ NaCl ion pair
[illustration: a bar of gold] 1 mole of Gold (Au) = 6.02 x 10²³ Au atoms
[photo: a packet of sugar labeled SUGAR] 1 mole of sugar (C12H22 O11) = 6.02 x 10²³ sugar (C12H22 O11)
[illustration: a glass of water] 1 mole of water (H2O) = 6.02 x 10²³ H2O molecules
In counting the number of atoms, we use a constant number called Avogadro’s number which is equivalent to a MOLE. Understanding the basic concept of a mole is the key in relating mass, mole, and number of particles in elements, compounds and chemical reactions. This chemical calculation used in chemistry is known as stoichiometry.
One mole is the amount of substance that contains as many particles as there are present in 12 grams of Carbon-12 atom. The actual number of atoms in 12 g of Carbon-12 isotope is equal to 6.02×10²³ particles called Avogadro’s number, in honor of the Italian scientist Amadeo Avogadro.
1 mole ₁₂C = 12.00g ₁₂C = 6.02 x 10²³ ₁₂C atoms
Calculating Number of Mole Given the Mass or Vice Versa
Operationally, the number of moles is determined using the formula.
Mole = Mass (in g) / Formula or molecular mass
Let us calculate the number of moles of oxygen (O2) in 24.0 g of O2. From the definition of a mole, we know that 1 mole of O2 = 32.0 g.
Solution:
Mole = 24.0 g O2 x (1 mole O2 / 32.0 g O2)
Mole = 0.75 mole of O2
Mole-Mass Relationship and Calculation
Chemists generally use the mole as the unit for the numbers of atoms or molecules of a substance. In the previous discussion, molecular mass of any element can be determined by finding the atomic weight of the element on the periodic table.
By recognizing the relationship between the molecular mass, moles, and particles, scientists can use dimensional analyses to easily convert mass, number of moles of atoms or vice versa.
For simple mole to mass conversion, here is the general pattern:
| Cases | General Pattern |
|---|---|
| Case 1: No. of moles is given; mass is unknown | Mass = given number of moles x molar mass Mass = given number of moles x g/mol |
| Case 2: Mass is given; no. of moles is unknown | Number of moles = given mass X molar mass Number of moles = given mass x mol/g |
Case 1: No. of moles is given; mass is unknown
Problem: What is the mass in grams of 2 moles of magnesium?
Computation Process:
Step 1. Identify the given.
Given: 2 moles of magnesium 1 mole of Mg = 24 g Mg
Unknown: mass in grams of Mg 1 mole of Mg = 24 g Mg
Step 2. Identity the case on the table above and use the formula.
Case 1: Mass = given number of moles x g/mol
Step 3. Substitute the value in the equation.
Mass = 2 moles of Mg x (24 g Mg / 1 mol Mg) = 48 g of Mg
Case 2: Mass is given; no. of moles is unknown
Problem: What is the number of moles of 36 g of water (H2O)?
Computation Process:
Step 1. Identify the given and unknown.
Given: 36 g of H2O Unknown: number of moles and molar mass of water (H2O)
Step 2. Determine the molar mass of a compound
H = 1 g x 2 = 2 g O = 16 g x 1 = 16 g
The molar mass of water (H2O) is 18 g/mol
Step 3. Substitute the values in the equation, in this we will use the formula in case no. 2.
Number of moles = 36 g of H2O x (1 mol of H2O / 18 g of H2O) = 2 mol of H2O
The unit for the number of mole is expressed as mole or mol.
Mole-Number of Particles Relationship
From our previous discussion, you have already learned that is the mole can be used to relate masses of substance to the quantity of atoms therein. This is an easy way of determining how much of one substance can react with a given amount of another substance.
From moles of a substance, you can also find the number of atoms in a substance and vice versa.
In this part, let us find out how to convert moles and the number of atoms in each substance using Avogadro’s number.
We know that the number of particles present in 12 g of carbon is 6.02×10²³. This is known as Avogadro’s number. The number of particles (atoms, molecules, ions) is equal to Avogadro’s number 6.02 x 10²³ in honor of the scientist Amedeo Avogadro.
Here is the formula that is used in determining the number of particles of a compound:
No. of particles = n X N
Where:
n = number of moles N = Avogadro’s number which has a constant value of 6.02 x 10²³
Let us try to analyze the sample problem.
Problem: Carbon dioxide is the by-product of the respiration of humans and animals. It is used by plants to perform photosynthesis. If a human released 3 moles of CO2 in a second, how many molecules of CO2 are there?
Computation Process:
Step 1: Identify the given and unknown.
Given: 3 moles of CO2 Unknown: No of particles (molecules)
Step 2: Substitute the given in the equation.
No. of particles = 3 moles x 6.02 x10²³ CO2 molecules = 18.06 x 10²³ CO2 molecules = 1.806 x 10²⁴ CO2 molecules
What’s More
Activity 1. Molecular Mass
Compute the molecular mass of the given compounds. Write your answer on a separate sheet of paper.
- Copper (II) Sulfate (CuSO4)
| Element | Quantity | Average atomic mass | Subtotal | ||
|---|---|---|---|---|---|
| Cu | X | = | |||
| S | X | = | |||
| O | X | = | |||
| Molecular Mass |
- Potassium Permanganate (KMnO4)
| Element | Quantity | Average atomic mass | Subtotal | ||
|---|---|---|---|---|---|
| K | X | = | |||
| Mn | X | = | |||
| O | X | = | |||
| Molecular Mass |
- Lead (II) Nitrate Pb(NO3)2
| Element | Quantity | Average atomic mass | Subtotal | ||
|---|---|---|---|---|---|
| Pb | X | = | |||
| N | X | = | |||
| O | X | = | |||
| Molecular Mass |
- Ammonium Sulfate (NH4)2SO4
| Element | Quantity | Average atomic mass | Subtotal | ||
|---|---|---|---|---|---|
| N | X | = | |||
| H | X | = | |||
| S | X | = | |||
| O | X | = | |||
| Molecular Mass |
Activity 2. What’s the code?
To find the answer to the question, look at the solution section below. Write the answer to the problems on the line (indicate the letter that correspond to each answer). See the given examples. You may write your answer on a separate sheet of paper.
[illustration: a safe with a combination keypad and handle]
Solution Section:
(A) 0.02 mol (B) 2.03 mol (C) 3.67 mol (D) 0.37 mol (E) 8.02 g (F) 9.03 g (G) 0.500 mol (H) 5.45 g (I) 4.80 g (J) 921.95 g
- What is the mass of 0.042 mole Octane (C8H18)?
- What is the mass of 4.02 mol Barium nitrite Ba(NO2)2?
- How many moles are there in 19.0 g of Fluorine (F2)?
- How many moles are there in 44.0 g of Sodium dihyrogen phosphate (NaH2PO4)?
- How many moles are there in 1.04 g Sodium chloride (NaCl)?
Activity 3. Proper Label!
Safety inside the chemistry laboratory is important. As part of safety protocols in the laboratory all chemicals must be properly stored and labelled. Let us write the necessary information for each chemical in the laboratory.
Directions: Complete the table by providing the necessary information. Write your answer on a separate sheet of paper.
| Substance | Molecular Mass | Kind of particles | Mass (g) | No. of moles | No. of particles |
|---|---|---|---|---|---|
| Gold (Au) | Atom | 197 | 1 | ||
| Sugar (C2H22O11) | molecule | 2 | |||
| Carbon dioxide (CO2) | 3 | ||||
| Sulfur (S) | 32 | 64 |
Activity 4. What’s the number?
Let us do some dimensional analyses to practice your skills and apply what you have learned about mole-number of particles relationship
6.02×10²³ particles = 1 mole
Directions: Convert the following units. Write your solution and answer on a separate sheet of paper.
- What is the number of particles in 0.500 mole of Al?
- What is the number of moles of S in 1.8 x 10²³ S atoms?
- What is the number of particles in 1.5 moles of CO₂?
- What is the number of moles of Zn in 4.22×10²³ atoms?
- How many moles is 25.2 g of Fe?
Activity 5. Are you related? (Mass, Mole, No. of particles)
You almost mastered the skills in expressing the mass of a substance using the mole concepts. Let us try to analyze the given data and answer the following questions. Write your answer on a separate sheet of paper.
| Substance | No. of particles | No. of Moles | Molecular Mass |
|---|---|---|---|
| Water H2O | 6.02×10²³ | 1 | 18 amu |
| Gold (Au) | 6.02×10²³ | 1 | 197 amu |
| Sugar (C12H22O11) | 6.02×10²³ | 1 | 342 amu |
| Salt (NaCl) | 6.02×10²³ | 1 | 58 amu |
| Sulfur (S) | 6.02×10²³ | 1 | 32 amu |
- What is the relationship among mass, mole and no. of particles of a given substance?
- Help Sally arrange her ideas the concept of mole. Which of these ideas about mole is incorrect? Why?
[illustration: girl with glasses thinking, with three thought bubbles]
- a. One mole of a substance contains a fixed number of particles.
- b. One mole of different substances contains the same number of particles, but they have different masses.
- c. One mole of different substances has different masses and different number of particles.
What I Have Learned
Determine the word/s that correctly complete s the statement. Write your answer on a separate sheet of paper.
- The __________________ is the sum average of the atomic weights of the atoms in its empirical formula.
- The molecular mass of a molecule is its average mass as calculated by adding the __________________ of the atoms in the molecular formula.
- __________________ is the unit use to express formula mass.
- Molecular mass is used for __________________ compounds.
- __________________ is the unit use to express molecular mass.
- The quantity of a substance which contains the same number of particles is called __________________.
- The actual number of atoms in 12 g of Carbon-12 isotope is equal to __________________ particles.
- In counting the number of atoms, we use a constant number called __________________.
- The number of particles (atoms, molecules, ions) is equal to Avogadro’s number 6.02 x 10²³ in honor of the scientist __________________.
- In converting mass, number of moles of atoms or vice versa scientist use __________________.
What I can do
There are so many applications of mole concepts around us. Can you solve this problem using the mole concept in expressing the mass, moles and number of particles of a substance?
Ammonium phosphate (NH₄)₃PO₄ is a compound that is often used by farmers as fertilizers. If Mang Ambo has 100 grams of this compound. Can you calculate its molecular mass, numbers of moles, and its number of particles? Write your answer on a separate sheet of paper.
A. Molecular mass of (NH₄)₃PO₄
B. Number of moles of (NH₄)₃PO₄
C. Number of particles
Assessment
Choose the letter of the best answer. Write your answers on a separate sheet of paper.
Which of these is the quantity of a substance containing the same number of particles?
- A. Density
- C. Mole
- B. Mass
- D. Volume
Which statement is TRUE about the different substance having the same number of moles?
- A. They have equal masses.
- B. They have equal numbers of particles.
- C. They have equal volumes per unit mass.
- D. They have the same amounts of energy.
Which molecule has the largest mass per molecule?
- A. H₂
- C. CO₂
- B. Cl₂
- D. C₂H₅OH
Which of these values represent the number of particles in one mole of a substance?
- A. 6.02×10²²
- C. 6.02×10²⁴
- B. 6.02×10²³
- D. 6.02×10²⁵
Who among these chemists and physicists made use of the mole concept to represent the number of particles in a substance?
- A. Amedeo Avogadro
- C. John Dalton
- B. Jacques Charles
- D. Robert Boyle
Which of these sets of units is used to represents molecular mass?
- A. g
- C. Kg
- B. g/mol
- D. mg
Which of these values is the correct molar mass for Sodium chloride (NaCl)?
- A. 58.5 g/mol
- C. 38.1 g/mol
- B. 45.2 g/mol
- D. 11.3 g/mol
Which is equivalent to one mole of Ca(NO₃)₂?
- A. 40 g Ca(NO₃)₂; 6.02 x 10²³ particles
- B. 164 g Ca(NO₃)₂; 12.04 x 10²³ particles
- C. 328 g Ca(NO₃)₂; 6.02 x 10²³ particles
- D. 164 g Ca(NO₃)₂; 6.02 x 10²³ particles
The molecular mass of water is 18 g/mol. How many moles of water is found in 6 grams of water (H₂O)?
- A. 0.52 mol
- C. 0.33 mol
- B. 1.80 mol
- D. 0.48 mol
What is the mass of 2.5 mol CaCl₂?
- A. 420 g
- B. 720 g
- C. 120 g
- 277 g
[transcriber’s note: “277 g” appears at the left margin below option C, without a letter; it is transcribed as printed]
Additional Activities
We are almost done! You did great in the previous part. Sally cannot determine the mass of harvest on their farm; would you like to help her? Using your knowledge about the basic mole concept, let us try to calculate the given substances.
Directions: Solve the given problems below. Write you solution and answer on the box below.
- How many sunflower seeds are equal to 3.50 moles of sunflower seeds?
- How many strawberries are equal to 7.50 moles of strawberries?
- How many moles of rice grains are equal to 1.807×10²⁴ grains of rice?
Answer Key
[illustration: key icon beside the heading]
[transcriber’s note: the answer key on this page is printed upside down; the text below is transcribed in reading order]
What I Know
- A
- C
- B
- B
- C
- C
- D
- A
- B
- D
What’s In
- Diagram A
- B and C
- B has a double bond in its carbon while C has triple bond.
- Hydrogen and Carbon
What’s New
- Dozen – 12
- Case – 24
- Ream – 500
- Mole – 6.02 x 10²³
What’s More
Activity 1. Molecular mass
- 160 g/mol
- 158 g/mol
- 331 g/mol
- 132 g/mol
Activity 2. What’s the code?
A D G J I
[transcriber’s note: the letters are printed in boxes; their order is reversed by the upside-down printing]
Activity 3. Proper Label
| Substance | Molecular mass | Kind of particles | No. of moles | No. of particles |
|---|---|---|---|---|
| Gold | 197 | Atom | 1 | 6.02×10²³ |
Activity 4. What’s the number?
- 3.01 x 10²³ molecules
- 0.299 moles
[transcriber’s note: the following lines continue the Activity 4 answers from the previous page, printed upside down]
- 9.03 x 10²³ molecules
- 7.010 moles of Zn [?]
- 0.451 moles of Fe
Activity 5. Are you related? (Mass, Mole, No. of particles)
[transcriber’s note: the header row of this answer table is not legible in the image; the rows are transcribed in printed order]
| [illegible] | [illegible] | [illegible] | [illegible] | [illegible] | [illegible] |
|---|---|---|---|---|---|
| Sugar | 342 | Molecule | 684 | 2 | 12.04×10²³ |
| Carbon dioxide | 44 | Molecule | 132 | 3 | 18.06×10²³ |
| Sulfur | 32 | atom | 64 | 2 | 12.04×10²³ |
- The no. of moles of a compound is related to its mass through the molar mass. The no. of moles is related to the number of particles through the Avogadro number.
- The incorrect idea is letter B – The correct statement is different materials of one mole each have different masses but the same number of particles.
What I Have Learned
- Formula Mass
- Atomic weight
- amu (atomic mass unit)
- Covalent
- g/mol (grams per mole)
- Mole (mol)
- 6.02 x 10²³
- Avogadro’s number
- Avogadro
- Dimensional analysis
What I can do
- 149 g/mol
- 0.67 mole
- 4.03 x 10²³
Assessment
- C
- B
- B
- B
- A
- C [?]
- A
- D
- B [?]
- D
Additional Activities
- 2.11 x 10²³ sunflower seeds
- 4.54 x 10²³ strawberries
- 3.002 moles of rice grains
References
Books:
Juan, Evangeline B., 2019. 2ND Quarter: Science Progressive Questions in Grade 9 Chemistry. Malabon City, Metro Manila: SDO-Malabon City.
Tabligan, Merry Chris T. 2019. 2nd Quarter: Science Progressive Formative Assessment Grade 9: Chemistry – Matter. Malabon City, Metro Manila: SDO-Malabon City.
Project EASE (Effective Alternative Secondary Education). Chemistry Module 16 Stoichiometry. Pasig City, Metro Manila: Department of Education
Online Resources:
carboxylicacid. “MRS. RENEROSA G. CAMAY’S SIM.” Education, 02:44:56 UTC. https://www.slideshare.net/carboxylicacid/sim-in-mole-2-powerpoint.
Image Sources:
DepEd – Bureau of Learning Resources (BLR) Illustrations. Pair of slippers https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Molecules. https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Salt. https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Gold bar. https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Bag of sugar https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Glass of water. https://lrmds.deped.gov.ph/
DepEd – Bureau of Learning Resources (BLR) Illustrations. Vault. https://lrmds.deped.gov.ph/
Bautista, Ramil A., Girl character. https://picfix.com
Bautista, Ramil A., Hydrocarbons. Microsoft paint
Esguerra, Dalisay E., Tray of eggs. Microsoft paint.
Esguerra, Dalisay E., Bottles. Microsoft paint.
Esguerra, Dalisay E., Ream of paper. Microsoft paint.
For inquiries or feedback, please write or call:
Department of Education – Bureau of Learning Resources (DepEd-BLR)
Ground Floor, Bonifacio Bldg., DepEd Complex Meralco Avenue, Pasig City, Philippines 1600
Telefax: (632) 8634-1072; 8634-1054; 8631-4985
Email Address: blr.lrqad@deped.gov.ph * blr.lrpd@deped.gov.ph
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