This is Mathematics 9 Quarter 1 Module 7, Relation of Roots and Coefficient of a Quadratic Equation, a Week 2 self-learning module for Grade 9 learners. Most learners check the solutions of a quadratic equation by substituting them back into the equation. This module teaches another way: using the relationship between the roots and the coefficients a, b, and c to check roots and to build a quadratic equation from given roots.
On this page 6 sections
What learners will learn
The module has one learning competency. Learners will be able to:
- describe the relationship between the coefficients and the roots of a quadratic equation (M9AL-Ib-4)
Parts of the module
| Part | What it contains |
|---|---|
| What I Know | A 10-item multiple-choice pretest |
| What’s In | A review activity: find a, b, c, the roots, and their sum and product for x² + 4x − 21 = 0 and x² + 8x − 20 = 0 |
| What’s New | A short profile of François Viète, the French mathematician behind Viète’s formulas |
| What is It | The derivation of the sum and product formulas, with two worked examples |
| What’s More | Practice on finding sums, products, and equations from roots |
| What I Have Learned | A summary of the two formulas |
| What I Can Do | More practice items, including one with letter coefficients |
| Assessment | A 10-item multiple-choice post-test |
| Additional Activities and Problem-Based Worksheet | Word problems about rectangular lots |
Key ideas: sum and product of the roots
For a quadratic equation in standard form ax² + bx + c = 0, where a, b, and c are real numbers and a ≠ 0, with roots x₁ and x₂:
- Sum of the roots: x₁ + x₂ = −b/a
- Product of the roots: x₁ · x₂ = c/a
The module derives these from the quadratic formula. Adding the two roots cancels the square root parts and leaves −2b/2a, or −b/a. Multiplying them gives (b² − (b² − 4ac))/4a², which simplifies to c/a.
If you divide ax² + bx + c = 0 by a, you get x² + (b/a)x + c/a = 0. So when the leading coefficient is 1, the coefficient of x is the negative of the sum of the roots, and the constant term is the product of the roots. This lets you write an equation as x² − (sum)x + (product) = 0.
Example 1: Sum and product without solving
For 4x² + 2x − 5 = 0, a = 4, b = 2, and c = −5.
- Sum: −b/a = −2/4 = −1/2
- Product: c/a = −5/4
Example 2: Forming an equation from its roots
Find the quadratic equation whose roots are 1/5 and 3/7.
- Sum: 1/5 + 3/7 = 22/35
- Product: 1/5 · 3/7 = 3/35
- Equation: x² − (22/35)x + 3/35 = 0, or 35x² − 22x + 3 = 0 after multiplying by 35
Applying the idea to a word problem
The Problem-Based Worksheet, The Rectangular Garden, describes a lot with a perimeter of 38 m and an area of 84 m². With width x and length y, xy = 84 and 2x + 2y = 38, so x + y = 19. The semi-perimeter is the sum and the area is the product, giving x² − 19x + 84 = 0. Solving with the quadratic formula gives 12 and 7, so the lot is 12 m long and 7 m wide.
How to use this module
- Answer the What I Know pretest on your answer sheet. Check it, note the items you missed, and look for the right answers as you work through the module.
- Do the What’s In review using what you learned in the previous module on solving quadratic equations.
- Study What is It closely, especially the two worked examples.
- Work on What’s More and What I Can Do. The module invites you to discuss your ideas with someone at home.
- Take the Assessment. If your answer is not among the choices, write E with your final answer.
- Try the Additional Activities and the Problem-Based Worksheet.
For learners: Check your work with the answer key at the end of the module only after you finish each part.
For parents: Your child can work through the parts in order. You can help by asking them to explain why the sum is −b/a and the product is c/a.
For teachers: The answer key covers the pretest, the review activity, What’s More, What I Can Do, the Assessment, and the Problem-Based Worksheet. Review it before use, because one printed answer appears to be incorrect (see the FAQ).
Frequently asked questions
What grade and quarter is this module for?
It is for Grade 9 Mathematics, Quarter 1, Module 7, and it is labeled for Week 2. Its learning competency code is M9AL-Ib-4.
What is the formula for the sum and product of the roots of a quadratic equation?
For ax² + bx + c = 0, the sum of the roots is −b/a and the product of the roots is c/a. The module derives both from the quadratic formula.
How do you form a quadratic equation from its roots?
Find the sum and the product of the roots, then write x² − (sum)x + (product) = 0. Clear any fractions by multiplying through. For roots 1/5 and 3/7, this gives 35x² − 22x + 3 = 0.
Does the module have an answer key?
Yes. It has answers for the pretest, the review activity, What’s More, What I Can Do, the Assessment, and the Problem-Based Worksheet. The key gives 4 as the product for 4x² + 6x + 3 = 0 in What’s More, but by the module’s own formula c/a, the product is 3/4.
Who is François Viète?
He was a French mathematician, lawyer, and consultant to Kings Henry III and IV of France. He discovered Viète’s formulas, which connect the roots and coefficients of a polynomial.
Full text of the module
The text below is a transcription of the PDF above, as printed.
Mathematics Quarter 1-Module 7: Relation of Roots and Coefficient of a Quadratic Equation
Week 2 Learning Code – M9AL-Ib-4
[illustration: teacher on a computer screen and students using laptops, tablets, and books]
GRADE 9 Learning Module for Junior High School Mathematics
Quarter 1 – Module 7 – New Normal Math for G9 First Edition 2020 Copyright © 2020
Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties.
Borrowed materials (i.e. songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them.
Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio
Development Team of the Module
Writers: Rowena F. Reyes – TI, Analynn M. Argel – MTII
Editor: Sally C. Caleja – Head Teacher VI, Ma. Teresa M. Mallari – Head Teacher VI, Maita G. Camilon – Head Teacher VI
Validators: Remylinda T. Soriano, EPS, Math; Angelita Z. Modesto, PSDS; George B. Borromeo, PSDS
Illustrator: Writers
Layout Artist: Writers
Management Team: Malcolm S. Garma, Regional Director; Genia V. Santos, CLMD Chief; Dennis M. Mendoza, Regional EPS in Charge of LRMS and Regional ADM Coordinator; Maria Magdalena M. Lim, CESO V, Schools Division Superintendent; Aida H. Rondilla, Chief-CID; Lucky S. Carpio, Division EPS in Charge of LRMS and Division ADM Coordinator
Module 7 Relation of the Roots and Coefficients of a Quadratic Equation
It is common that if we check the solutions of a quadratic equation, we simply substitute the solution to the original equation. But there is another method for this. In this module, you will discover the relationship of the roots and coefficients of a quadratic equation and apply this concept in checking the roots and in constructing a quadratic equation.
What I Need to Know
Learning Competency
The learners will be able to:
- describe the relationship between the coefficients and the roots of a quadratic equation. M9AL-Ib-4
What I Know
Find out how much you already know about the relation of the roots and coefficients of a quadratic equation. Write the letter that you think is the best answer to each question on your answer sheet. Answer all items. After taking and checking this short test, take note of the items that you were not able to answer correctly and look for the right answer as you go through this module.
Given the quadratic equation $ax^2 + bx + c = 0$ where $a, b, c$ are real numbers and $a \neq 0$, which of the following is the sum of its roots?
a. $a$
b. $c$
c. $-\frac{b}{a}$
d. $\frac{c}{a}$Which of the following is the product of the roots of $ax^2 + bx + c = 0$?
a. $\frac{c}{a}$
b. $-\frac{b}{a}$
c. $c$
d. $a$What is the sum of the roots of the quadratic equation $2x^2 + 10x – 14 = 0$?
a. $-5$
b. $5$
c. $7$
d. $-7$In the quadratic equation $2x^2 + 10x – 14 = 0$, which of the following is the product of its roots?
a. $-5$
b. $5$
c. $7$
d. $-7$The roots of a quadratic equation are $-9$ and $3$. Which of the following quadratic equations has these roots?
a. $x^2 – 9x + 3 = 0$
b. $x^2 + 6x – 27 = 0$
c. $9x^2 – 3x + 27 = 0$
d. $3x^2 – 9x + 27 = 0$The sum of the roots of a quadratic equation is $-8$. If one of the roots is $7$, which of the following is the quadratic equation?
a. $x^2 + 8x – 105 = 0$
b. $x^2 – 8x + 105 = 0$
c. $x^2 + 8x + 105 = 0$
d. $x^2 – 8x – 105 = 0$The product of the roots of a quadratic equation is $48$. If one of the roots is $-16$, which of the following could be the equation?
a. $x^2 – 48 = 0$
b. $x^2 + 16 = 0$
c. $x^2 + 19x + 48 = 0$
d. $x^2 – 19x + 48 = 0$$\frac{3+\sqrt{7}}{4}$ and $\frac{3-\sqrt{7}}{4}$ are the roots of which of the following quadratic equations?
a. $8x^2 – 12x + 1 = 0$
b. $8x^2 + 12x + 1 = 0$
c. $12x^2 – 8x + 1 = 0$
d. $12x^2 – 8x – 1 = 0$Let $s$ and $p$ be the roots of the equation $4x^2 – tx = n$. What is $s + p$?
a. $\frac{t}{4}$
b. $\frac{n}{4}$
c. $4$
d. $-t$What is the value $k$ if one root of $3kx^2 – 2kx + 9 = 0$ is $1$?
a. $-18$
b. $-9$
c. $9$
[transcriber’s note: choice d is not printed for item 10]
What’s In
[transcriber’s note: “Critical Thinking” is printed in a callout beside the heading “WHAT’S IN”]
Refer to the two quadratic equations below. Use the concepts learned in the previous module to fill in the blanks with the correct answer. Then, answer the question at the end.
[transcriber’s note: the two equations are arranged as two columns of boxes with steps in order from top to bottom; the table below follows that order]
| Step | First equation | Second equation |
|---|---|---|
| Equation | $x^2 + 4x – 21 = 0$ | $x^2 + 8x – 20 = 0$ |
| What are the values of: | 1. $a = $ ______, 2. $b = $ ______, 3. $c = $ ______? | 1. $a = $ ______, 2. $b = $ ______, 3. $c = $ ______? |
| Using any method, what are the roots? | 1. $x_1 = $ ______ 2. $x_2 = $ ______ | 1. $x_1 = $ ______ 2. $x_2 = $ ______ |
| Perform the indicated operation. | 1. $x_1 + x_2 = $ ______ 2. $x_1 \cdot x_2 = $ ______ | 1. $x_1 + x_2 = $ ______ 2. $x_1 \cdot x_2 = $ ______ |
Question:
- What do you observe about the sum and product of the roots in relation to the values of a, b, and c?
What’s New
[transcriber’s note: “Communication” is printed in a callout beside the heading “WHAT’S NEW”]
The Author of Analytic Art
[photo: black-and-white portrait of a bearded man in a high-collared robe]
[illustration: “Who is HE?” lettering]
- ✓ He was a French Mathematician, lawyer, and consultant to Kings Henry III and IV of France.
- ✓ He made some significant developments in Algebra.
- ✓ He wrote some books about geometry and trigonometry.
- ✓ He calculated $\pi$ to decimal places using a polygon with 393 216 sides.
- ✓ He discovered the Viète’s formula which is the connection between the roots and coefficients of polynomial.
Since a quadratic expression is considered as a polynomial, hence, the person behind in this module’s topic is François Viète.
What is It
The generalization about the sum and product of the roots of a quadratic equation can be derived by using the quadratic formula as a method in finding the roots.
Given the standard form, $ax^2 + bx + c = 0$, where $a, b, c$ are real numbers and $a \neq 0$, the roots can be expressed as:
$$x_1 = \frac{-b+\sqrt{b^2-4ac}}{2a} \quad \text{and} \quad x_2 = \frac{-b-\sqrt{b^2-4ac}}{2a}.$$
So,
| SUM | PRODUCT |
|---|---|
| $x_1 + x_2$ $= \frac{-b+\sqrt{b^2-4ac}}{2a} + \frac{-b-\sqrt{b^2-4ac}}{2a}$ $= \frac{-2b}{2a}$ $= -\frac{b}{a}$ | $x_1 \cdot x_2$ $= \frac{-b+\sqrt{b^2-4ac}}{2a} \cdot \frac{-b-\sqrt{b^2-4ac}}{2a}$ $= \frac{b^2-(b^2-4ac)}{4a^2}$ $= \frac{b^2-b^2+4ac}{4a^2}$ $= \frac{4ac}{4a^2}$ $= \frac{c}{a}$ |
[transcriber’s note: table continued from the previous page]
| SUM | PRODUCT |
|---|---|
| Therefore, the sum of the roots of a quadratic equation in terms of its coefficients is denoted by: $x_1 + x_2 = -\frac{b}{a}$ | On the other hand, the product of the roots of a quadratic equation in terms of its coefficients is denoted by: $x_1 \cdot x_2 = \frac{c}{a}$ |
Now let’s go back to the standard form of a quadratic equation, $ax^2 + bx + c = 0$.
If we divide both sides of the equation by $a$, the coefficient of $x^2$, the equation becomes
$$x^2 + \frac{b}{a}x + \frac{c}{a} = 0$$
What do you notice?
This implies that, in a quadratic equation of the form $ax^2 + bx + c = 0$, where $a = 1$, the negative of the sum of the roots is the coefficient of $x$, and the constant term is the product of the roots. Similarly, given the sum and product of the roots, we can obtain the quadratic equation.
Example 1: Without solving for the solutions of the quadratic equation, $4x^2 + 2x – 5 = 0$, find the sum and product of its roots.
Solution: Given the equation $4x^2 + 2x – 5 = 0$, we have $a = 4$, $b = 2$ and $c = -5$.
Hence, the sum of the roots is $-\frac{b}{a} = -\frac{2}{4} = \boxed{-\frac{1}{2}}$
the product of the roots is $\frac{c}{a} = \boxed{-\frac{5}{4}}$
Example 2: Using the concept of the sum and product of roots, form the quadratic equation whose roots are $\frac{1}{5}$ and $\frac{3}{7}$.
Solution:
Sum of the roots: $\frac{1}{5} + \frac{3}{7} = \frac{7+15}{35} = \boxed{\frac{22}{35}}$ [transcriber’s note: arrow label beside this line reads $-\frac{b}{a}$]
Product of the roots: $\frac{1}{5} \cdot \frac{3}{7} = \boxed{\frac{3}{35}}$ [transcriber’s note: arrow label beside this line reads $\frac{c}{a}$]
Hence, following the equation form $x^2 + \frac{b}{a}x + \frac{c}{a} = 0$, we have:
$$x^2 – \frac{22}{35}x + \frac{3}{35} = 0 ;\rightarrow; \boxed{35x^2 – 22x + 3 = 0}$$
What’s More
[transcriber’s note: “Collaboration, Critical Thinking” is printed in a callout beside the heading “WHAT’S MORE”]
I. Find the sum and product of the roots of each equation placed inside the rectangle:
$2x^2 – 5x + 1 = 0$
SUM: ____________
PRODUCT: ______$4x^2 + 6x + 3 = 0$
SUM: ____________
PRODUCT: ______$2x^2 + 11x – 15$
SUM: ____________
PRODUCT: ______
[transcriber’s note: the third equation is printed without “= 0”]
II. Find the quadratic equation whose roots are given below. You may discuss your idea to your housemate.
$x_1 = 2$
$x_1 = 3$
QUADRATIC EQUATION: __________________$x_1 = \frac{1}{2}$
$x_1 = \frac{2}{5}$
QUADRATIC EQUATION: __________________$x_1 = \sqrt{5}$
$x_1 = -\sqrt{5}$
QUADRATIC EQUATION: __________________
III. If $s$ and $p$ are the roots of the equation $5x^2 – mx = n$, what is $s + p$?
What I Have Learned
Given the quadratic equation of the form $ax^2 + bx + c = 0$, where $a, b, c$ are real numbers and $a \neq 0$, the following are the relations regarding its roots $x_1$ and $x_2$ and its coefficients.
(a) The sum of the roots is the additive inverse of the quotient of the coefficients $b$ and $a$ denoted by: $$x_1 + x_2 = -\frac{b}{a}$$
(b) The product of the roots is the quotient of the coefficients $c$ and $a$ denoted by: $$x_1 \cdot x_2 = \frac{c}{a}$$
WHAT I CAN DO
I. Without solving, find the sum and product of the roots of each of the following equations.
- 4𝑥² + 3𝑥 + 8 = 0
- 𝑑² + 7𝑑 − 5 = 0
- 6𝑥² − 5𝑥 + 8 = 0
- 2𝑧² + 7𝑧 − 3 = 0
- 10𝑚² − 8𝑚 + 3 = 0
II. Find the quadratic equations whose root are:
- 1/2, 3
- 7, −3
- −4, 7
- 1/2, 2/3
- 11/2, 5/2
III. If 𝑟 and 𝑡 are the roots of the equation 7𝑥² − 𝑔𝑥 = 𝑛, what is 𝑟 + 𝑡?
ASSESSMENT
Write the letter of the correct answer on your answer sheet. If your answer is not among the choices, write E together with your final answer.
Given the quadratic equation 𝑎𝑥² + 𝑏𝑥 = −𝑐 where 𝑎, 𝑏, 𝑐 are real numbers and 𝑎 ≠ 0, which of the following is the product of its roots?
- A. 𝑎
- B. 𝑐
- C. −𝑏/𝑎
- D. 𝑐/𝑎
In the quadratic equation 𝑎𝑥² + 𝑏𝑥 = −𝑐, which of the following is the sum of its roots?
- A. 𝑐/𝑎
- B. −𝑏/𝑎
- C. 𝑐
- D. 𝑎
What is the sum of the roots of the quadratic equation 8𝑥² + 5𝑥 − 14 = 0 ?
- A. −5/8
- B. −5/14
- C. 5
- D. 14
In the quadratic equation 8𝑥² + 5𝑥 − 14 = 0, which of the following is the product of its roots?
- A. −5
- B. −7/4
- C. 5
- D. 7/4
The roots of a quadratic equation are 6 and -3. Which of the following quadratic equations has these roots?
- A. 𝑥² − 3𝑥 − 18 = 0
- B. 𝑥² + 3𝑥 + 18 = 0
- C. 𝑥² − 3𝑥 + 18 = 0
- D. 𝑥² + 3𝑥 − 18 = 0
Let 𝑠 and 𝑝 be the roots of the equation 𝑥² − 𝑡𝑥 = 𝑛. What is 𝑠𝑝?
- A. 𝑛
- B. −𝑛
- C. 𝑡
- D. −𝑡
If (2+√3)/5 and (2−√3)/5 are the roots, which of the following is the quadratic equation?
- A. 25𝑥² − 20𝑥 + 1 = 0
- B. 25𝑥² + 20𝑥 − 1 = 0
- C. 25𝑥² − 20𝑥 − 1 = 0
- D. 25𝑥² + 20𝑥 + 1 = 0
The product of the roots of a quadratic equation is 36. If one of the roots is 9, which of the following could be the equation?
- A. 𝑥² + 13𝑥 + 48 = 0
- B. 𝑥² − 13𝑥 − 48 = 0
- C. 𝑥² − 13𝑥 + 36 = 0
- D. 𝑥² + 13𝑥 − 48 = 0
What is the value 𝑘 if one root of (3𝑘+1)𝑥² − 5𝑘𝑥 − 5 = 0 is 2?
- A. −1/2
- B. 1/2
- C. 5
- D. -5
The sum of the roots of a quadratic equation is 5. If one of the roots is 1, which of the following is the quadratic equation?
- A. 𝑥² + 5𝑥 − 4 = 0
- B. 𝑥² − 5𝑥 + 4 = 0
- C. 𝑥² + 5𝑥 + 4 = 0
- D. 𝑥² − 5𝑥 − 4 = 0
ADDITIONAL ACTIVITIES
Critical Thinking and Creativity
ENCLOSED! Mang Kevin owns a rectangular lot. The perimeter of the lot is 100 meters and the area is 450 square meters.
[photo: aerial view of a fenced rectangular lot]
Speech bubble: Using the concept of the sum and product of roots of a quadratic equation, how would you determine the length and the width of the rectangular lot? Provide a quadratic equation representing this scenario.
1source: https://www.thisiscolossal.com/tags/assemblage/
PROBLEM – BASED WORKSHEET
Read and study the given scenario. Then answer the questions that follow.
The Rectangular Garden
Ms. Ann bought a rectangular lot with a perimeter of 38m and an area of 84m².
[illustration: plain gray rectangle]
Supposing the width and the length are x and y, respectively,
- What equations represent the area and perimeter of the lot?
- Use the sum and product of the roots to find the quadratic equation that describes the situation.
- Find the dimensions of the rectangular lot.
E-Search
You may also check the following link for your reference and further learnings on solving quadratic equation using quadratic formula.
- https://www.khanacademy.org/math/math-for-fun-and-glory/aime/2003-aime/v/sum-of-polynomial-roots-proof
- https://www.youtube.com/watch?v=D57Gg7CGsTI
REFERENCES
Morgan, F. M., & Paige, B. L. (n.d.). Algebra 2. America: Henry Holt and Company.
Oronce, O. A., Santos, G. C., & Ona, M. I. (n.d.). Interactive Mathematics III (Concepts,Structures, adn Metods for High School. Manila: Rex Book Store
WHAT I KNOW
C 1. A 2. A 3. D 4. B 5. A 6. C 7. A 8. A 9. B 10.
ASSESSMENT
D 1. B 2. A 3. B 4. A 5. B 6. A 7. C 8. B 9. B 10.
PROBLEM – BASED WORKSHEET
Solutions:
For the area of the lot: 𝑥𝑦 = 84
For the perimeter of the lot: 2𝑥 + 2𝑦 = 38The area represents the product of the roots while the semi perimeter, 𝑥 + 𝑦 = 19, represents the sum of the roots. Thus, the equation will be: 𝑥² − 19𝑥 + 84 = 0
Solving for 𝑥 using quadratic formula:
𝑥 = (−𝑏 ± √(𝑏² − 4𝑎𝑐)) / 2𝑎
𝑥 = (−(−19) ± √((−19)² − 4(1)(84))) / 2(1)
𝑥 = (19 ± √25) / 2
𝑥 = (19 ± 5) / 2
Therefore:
𝑥 = (19 + 5)/2 or 𝑥 = (19 − 5)/2
𝑥 = 12 or 𝑥 = 7
Thus, the length of the lot is 12m and the width of the lot is 7m.
ANSWER KEY
RELAY!
| For 𝑥² + 4𝑥 − 21 = 0: | For 𝑥² + 8𝑥 − 20 = 0: |
|---|---|
| I. 1. 𝑎 = 1 2. 𝑏 = 4 3. 𝑐 = −21 II. 1. 𝑥₁ = −7 2. 𝑥₂ = 3 III. 1. 𝑥₁ + 𝑥₂ = −4 2. 𝑥₁ · 𝑥₂ = −21 | I. 1. 𝑎 = 1 2. 𝑏 = 8 3. 𝑐 = −20 II. 1. 𝑥₁ = −10 2. 𝑥₂ = 2 III. 1. 𝑥₁ + 𝑥₂ = −8 2. 𝑥₁ · 𝑥₂ = −20 |
WHAT’S MORE
I.
- 5/2, 1/2 [?]
- −3/2, 4 [?]
- −11/2, −15/2 [?]
II. C
- 𝑥² − 5𝑥 + 6 = 0
- 10𝑥² − 9𝑥 + 2 = 0
- 𝑥² − 5 = 0
III. 5𝑥² − 𝑚𝑥 = 𝑛 𝑎 = 5, 𝑏 = −𝑚 𝑥₁ + 𝑥₂ = −𝑏/𝑎 𝑠 + 𝑝 = −(−𝑚)/5 𝑠 + 𝑝 = 𝑚/5
WHAT I CAN DO
I.
- sum: −3/4; product: 2
- sum: −7; product: −5
- sum: 5/6; product: 4/3
- sum: −7/2; product: −3/2
- sum: 4/5; product: 3/10
II.
- 2𝑥² − 7𝑥 + 3 = 0
- 𝑥² − 4𝑥 − 21 = 0
- 𝑥² − 3𝑥 − 28 = 0
- 6𝑥² − 7𝑥 + 2 = 0
- 4𝑥² − 32𝑥 + 55 = 0
III. 7𝑥² − 𝑔𝑥 = 𝑛 𝑎 = 7, 𝑏 = −𝑔 𝑥₁ + 𝑥₂ = −𝑏/𝑎 𝑟 + 𝑡 = −(−𝑔)/7 𝑟 + 𝑡 = 𝑔/7
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