This is the Grade 9 Mathematics self-learning module for Quarter 1, Module 22, Equation of Quadratic Function Given Graphs and Zeros, set for Week 9. It is an Alternative Delivery Mode (ADM) module for Junior High School learners. It continues from the previous module, where learners found the equation of a quadratic function from a table of values. After this module, learners can write the equation of a quadratic function from its graph (its parabola) or from its zeros.
On this page 9 sections
What learners will learn
The module states one learning competency. Learners will be able to:
- Determine the equation of a quadratic function given a graph or zeros of the function (M9AL-Ij-15.2)
What the module covers
The module follows the usual ADM parts:
- What I Know: a 10-item multiple-choice pretest
- What’s In: a review where learners read the zeros from six parabolas
- What’s New: how a parabola can meet the x-axis
- What Is It: the lesson, with worked examples
- What’s More: practice from graphs and from 15 sets of zeros
- What I Have Learned: a summary
- What I Can Do: six graphs and ten sets of zeros to solve
- Assessment: a 10-item post-test
- Additional Activities: a project called “Parabola Around Us” and a problem-based worksheet about a kicked soccer ball
- Answer Key: answers, plus a rubric for the project
Key ideas: zeros and the parabola
The graph of a quadratic function is a smooth curve called a parabola. A parabola can cross the x-axis at two points, touch it at one point, or not meet it at all.
The zeros of a quadratic function are the x-coordinates of the points where the parabola meets the x-axis. On the graph, these are the x-intercepts. If the parabola never meets the x-axis, the function has no real zeros.
Finding the equation from a graph
The module says you can find the equation y = ax² + bx + c from a graph if you know any one of these:
- Three points on the parabola that are not x-intercepts or the vertex
- The x-intercepts and one other point, useful when the vertex coordinates are not whole numbers
- The vertex and one other point
The module adds that points with whole-number (integral) coordinates are easier to work with.
Example using the x-intercepts
A parabola crosses the x-axis at (−2, 0) and (1, 0) and crosses the y-axis at (0, −2).
- Since x = −2 and x = 1 are x-intercepts, (x + 2) and (x − 1) are factors: y = a(x + 2)(x − 1).
- The value of a is not always 1, so use the third point. Substitute (0, −2): −2 = a(0 + 2)(0 − 1), so −2 = −2a and a = 1.
- The equation is y = (x + 2)(x − 1), or y = x² + x − 2.
Example using the vertex
A parabola has its vertex at (−1, 0) and passes through (0, −1).
- Put the vertex into the vertex form: y = a(x + 1)² + 0.
- Substitute (0, −1): −1 = a(0 + 1)², so a = −1.
- The equation is y = −(x + 1)², or y = −x² − 2x − 1.
The points (−3, −4) or (1, −4) on the same graph would give the same value of a.
Finding the equation from the zeros
If x₁ and x₂ are the zeros, they are the roots of the matching quadratic equation, so the function can be written as y = (x − x₁)(x − x₂). Multiply the factors to get the standard form. The module’s examples:
| Zeros | Factors | Equation |
|---|---|---|
| 5 and −3 | (x − 5)(x + 3) | y = x² − 2x − 15 |
| 4 and 2/3 | (x − 4)(3x − 2) | y = 3x² − 14x + 8 |
| 1 + √3 (and its conjugate 1 − √3) | [(x − 1) − √3][(x − 1) + √3] | y = x² − 2x − 2 |
Two tips come from these examples:
- Fractions: for the zero 2/3, the factor (x − 2/3) is rewritten as (3x − 2), so the equation has whole-number coefficients.
- Irrational zeros: if 1 + √3 is a zero, its conjugate 1 − √3 is also a zero. Multiplying the two factors as a difference of two squares, (x − 1)² − (√3)², removes the square roots.
Real-life applications
- Parabola Around Us: learners find a real parabolic structure in the Philippines. The module’s example is the arched roof design of Mactan Cebu International Airport. Learners research its origin and size, place its picture on a coordinate plane using a graphing app, mark the vertex and other points, and find the equation of the parabola. A rubric in the answer key is used for scoring.
- Problem-based worksheet: a graph shows the height of a kicked soccer ball over time. Learners find the maximum height, when the ball reaches it, and the function h(t). The answer key gives a maximum height of 8 ft, reached after 0.5 second, with h(t) = −16t² + 16t + 4.
How to use this module
- Learners: Start with the pretest in What I Know and write your answers on a separate answer sheet. Check your answers and note the items you missed. Then work through the parts in order. Study the worked examples in What Is It before trying What’s More and What I Can Do, and go back to any example you find hard. Take the Assessment last.
- Parents: The module is written for learners to study on their own. You can help by checking that your child does the pretest first and finishes each part before moving on.
- Teachers: The answer key covers the pretest, the review, the practice sets, the post-test, the rubric, and the soccer-ball problem. Some answers in the key are hard to read, so check them against the worked methods before using them for grading.
The module’s E-Search page also suggests online videos and a Khan Academy exercise for further review.
Frequently asked questions
What grade and quarter is this module for?
It is for Grade 9 Mathematics, Quarter 1, Module 22, set for Week 9. Its learning code is M9AL-Ij-15.2.
How do you find a quadratic function from its zeros?
Write the function as y = (x − x₁)(x − x₂), using the two zeros, then multiply the factors. For example, the zeros 5 and −3 give y = (x − 5)(x + 3), which is y = x² − 2x − 15.
What do I need from a graph to find the equation of a quadratic function?
You need one of three things: three points on the parabola, the x-intercepts plus one more point, or the vertex plus one more point. Points with whole-number coordinates are easiest to use.
What if a zero has a square root, like 1 + √3?
Its conjugate, 1 − √3, is also a zero. Multiplying the two factors as a difference of two squares gives y = x² − 2x − 2.
Does the module have an answer key?
Yes. It has answers for the pretest, the review, the practice sets, the assessment, and the soccer-ball problem, plus a rubric for the Parabola Around Us activity.
Full text of the module
The text below is a transcription of the PDF above, as printed.
Mathematics Quarter 1 – Module 22
Equation of Quadratic Function Given Graphs and Zeros Week 9 Learning Code – M9AL-Ij-15.2
[illustration: teacher and learners at a computer, tablet, and laptop, with books and speech bubbles]
GRADE 9 Learning Module for Junior High School Mathematics
Quarter 1 – Module 22 – New Normal Math for G9 First Edition 2020 Copyright © 2020
Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties.
Borrowed materials (i.e. songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them.
Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio
Development Team of the Module
Writers: Analynn M. Argel- MTII Marvin G. Sollera -MTI
Editors: Sally C. Caleja- Head Teacher VI David Bowie U. Montales – Head Teacher III Cristina R. Solis – Head Teacher VI
Validators: Remylinda T. Soriano, EPS, Math Angelita Z. Modesto, PSDS George B. Borromeo, PSDS
Illustrator: Writers
Layout Artist: Writers
Management Team: Malcolm S. Garma, Regional Director Genia V. Santos, CLMD Chief Dennis M. Mendoza, Regional EPS in Charge of LRMS and Regional ADM Coordinator Maria Magdalena M. Lim, CESO V, Schools Division Superintendent Aida H. Rondilla, Chief-CID Lucky S. Carpio, Division EPS in Charge of LRMS and Division ADM Coordinator
GRADE 9 Learning Module for Junior High School Mathematics
WHAT I NEED TO KNOW
LEARNING COMPETENCY/IES The learners will be able to:
- Determine the equation of a quadratic function given a graph or zeros of the function. M9AL-Ij-15.2
WHAT I KNOW
Find out how much you already know about the equation of quadratic function given graphs and zeros. Write the letter that you think is the best answer to each question on your answer sheet. Answer all items. After taking and checking this short test, take note of the items that you were not able to answer correctly and look for the right answer as you go through this module.
- What do you call the graph of the quadratic function?
a. A) Circle B) Hyperbola C) Line D) Parabola - What are the zeros of the quadratic function = x² − 2x − 63 ?
A) – 9 & – 7 B) – 9 & 7 C) – 7 & 9 D) 7 & 9
[transcriber’s note: the printed function begins with “=” and no “y” is shown before it] - Which quadratic function has no zeros?
A) y = x² − 7 C) y = −x² + 7
B) y = −x² − 7 D) y = x² + 7x
For items 4 – 7, refer to the graph at the right.
- What is the vertex of the graph?
A) (0, –1)
B) (0, 1)
C) (– 1. 0)
D) (1, 0)
[chart: graph of a downward-opening parabola with its vertex on the x-axis near x = −1, drawn on a grid with x-axis ticks from −4 to 3 and y-axis ticks from 1 to −7; no values are printed on the chart beyond the axis ticks]
[transcriber’s note: the decorative banner printed beside this heading reads “PPREPREVIER!”]
GRADE 9 Learning Module for Junior High School Mathematics
WHAT I KNOW (continued)
- What is the zero(s) of the graph?
A) – 1 B) 0 C) 0 and – 1 D) None - What is the y-intercept of the graph?
A) – 1 B) 0 C) 1 D) None - Which equation define the given graph?
A) y = −x² − 2x − 1 C) y = −x² + 2x − 1
B) y = −x² − 2x + 1 D) y = −x² + 2x + 1 - What quadratic function that passes the point (1, 1) and to its only zero of 2?
A) y = x² − 4x − 4 C) y = x² − 4x + 4
B) y = x² + 4x − 4 D) y = x² + 4x + 4 - Find the equation of the quadratic function that doesn’t cross the x-axis and passes through the point (1, 7).
A) y = x² + 5 C) y = x² − 5
B) y = 2x² + 5 D) y = 2x² − 5 - What quadratic function contain the points (–1, 0), (1, 0) and (2, 3)?
A) y = −x² − 1 C) y = x² − 1
B) y = −x² + 1 D) y = x² + 1
WHAT’S IN
It is easier to understand this module if you know how to find the coordinates of points, particularly the zeroes, on a graph of a quadratic function. Recall that zeros of the quadratic function are actually the x-intercepts of the parabola that corresponds to it.
Determine the zeroes of the quadratic function whose graphs are given below:
[chart: graph of an upward-opening parabola crossing the x-axis near x = −2 and x = 2, with its lowest point just below the origin; grid with x-axis ticks from −4 to 4 and y-axis ticks from 4 to −4; no values are printed beyond the axis ticks]
[chart: graph of a downward-opening parabola crossing the x-axis near x = −1 and x = 4, with its highest point near y = 4; grid with x-axis ticks from −2 to 6 and y-axis ticks from 4 to −4; no values are printed beyond the axis ticks]
GRADE 9 Learning Module for Junior High School Mathematics
[chart: graph of an upward-opening parabola with its lowest point near the origin’s left side; grid with x-axis ticks from −5 to 3 and y-axis ticks from −8 to 1; no values are printed beyond the axis ticks]
[chart: graph of a downward-opening parabola with its vertex on the x-axis near x = −2; grid with x-axis ticks from −4 to 4 and y-axis ticks from 1 to −7; no values are printed beyond the axis ticks]
[chart: graph of an upward-opening parabola with its lowest point near x = −2, y = 2; grid with x-axis ticks from −5 to 3 and y-axis ticks from 1 to 8; no values are printed beyond the axis ticks]
[chart: graph of an upward-opening parabola with its lowest point near x = 1, y = 1; grid with x-axis ticks from −4 to 4 and y-axis ticks from 1 to 8; no values are printed beyond the axis ticks]
How did you find the activity? Were you able to spot the zeroes of the functions? Can you give other points on the parabola aside from the zeroes?
WHAT’S NEW
The graph of a quadratic function is a smooth curve called a parabola. A parabola may intersect the x–axis at two points, one point or no point at all.
[chart: three diagrams of a parabola with a vertical and horizontal axis line; the first intersects the horizontal line at two points, the second touches it at one point, the third does not meet it; labeled “two points”, “one point”, “no point”]
The x-coordinates of the points of intersection of the parabola and the x-axis are the zeroes of the quadratic function if it exists. Graphically, these are the x-
GRADE 9 Learning Module for Junior High School Mathematics
intercepts of the graph of a quadratic function. An x-intercept is a point on the graph that intersects the x-axis.
How will the points on the parabola, particularly the x-intercepts or the zeroes of the function, help in determine the equation of the quadratic function represented by the parabola?
WHAT IS IT
Deriving Quadratic Function Given Its Graph
If the graphs representing quadratic function y = ax² + bx + c is given, the equation representing the graph can be determined given any of the following conditions: a. Three points on the parabola none of which is an x-intercepts nor a vertex. b. The x-intercepts and a point on the parabola for graphs where the coordinates of the vertex are not integers. c. A vertex and a point on the parabola
Take note that it is more convenient if the points to consider are integral values. Study the examples below.
Example 1: Determine the quadratic function y = ax² + bx + c represented by the given graphs.
a. [chart: graph of an upward-opening parabola crossing the x-axis near x = −2 and x = 1, with its lowest point just below the origin; grid with x-axis ticks from −4 to 4; no values are printed beyond the axis ticks]
b. [chart: graph of a downward-opening parabola with its vertex at the origin’s left, near x = −1, y = 0; grid with x-axis ticks from −4 to 4 and y-axis ticks from 1 to −7; no values are printed beyond the axis ticks]
Solution: a. In the graph, the most convenient points to considers are the x-intercepts, (-2, 0) and (1,0) and the y-intercept (0, -2)
Given three points on the graph, you can find the equation of quadratic function creating systems of equation in three unknowns. However, if the x-intercepts are given, you can have an alternate solution:
GRADE 9 Learning Module for Junior High School Mathematics
If x = -2 and x = 1 are the x-intercepts, then (x + 2) and (x – 1) are factors of the equation of quadratic function. Thus,
y = a (x + 2) (x -1)
Take note that the value of a is not always 1 and the third point on the graph can help solve for the value of a. Substitute (0, -2) to the equation,
-2 = a (0 + 2) (0 – 1) -2 = -2a a = 1
Substitute the obtained value to the equation and simplify,
y = 1(x + 2) (x – 1) y = x² + x – 2
b. In this graph, the most convenient points to consider are the vertex (-1, 0), the y-intercept (0, -1) and any of the points (-3, -4) or (1, -4). However, if the vertex is given, you only need one of the point mentioned above.
Substitute the coordinates of the vertex (-1, 0) in the vertex form of the equation of quadratic function,
y = a (x+1)² + 0
Find the value of a by choosing any of the points (0, -1), (-3, -4) or (1, -4), then substitute:
-1 = a (0 + 1)² -1 = a
Substitute a = -1 in the equation, then transform it into y = ax² + bx + c;
y = -1 (x + 1)² → y = -x² – 2x – 1
Deriving Quadratic Function Given Its Zeroes
If the zeroes are given, then the equation of the quadratic function can be determined. Recall that zeroes, x₁ and x₂, of the function are the roots, of the equivalent quadratic equation,
y = (x – x₁) (x – x₂) → 0 = (x – x₁) (x – x₂)
Example 2: Determine the quadratic function given the following zeroes: a. 5, -3 b. 4, 2/3 c. 1 + √3
GRADE 9 Learning Module for Junior High School Mathematics
Solution: a. If 5 and -3 are zeroes of quadratic function y = ax² + bx + c, then (x – 5) and [x –(-3)] are factors of y, y = (x – 5) (x + 3) → y = x² – 2x – 15
b. If 4 and 2/3 are zeroes of quadratic function y = ax² + bx + c, then (x – 4) and (x – 2/3) are factors of y, y = (x – 4) (x – 2/3) y = (x – 4) (3x – 2) y = 3x² – 14x + 8
c. If 1 + √3 is a zero of quadratic function y = ax² + bx + c, then its conjugate 1 – √3 is also a zero of the function, thus [x + (1 + √3 )] and [x – (1 – √3 )] are factors of y,
y = [x – (1 + √3 )] [x – (1 – √3 )] y = [(x – 1) – √3 ] [ (x – 1) + √3 ] y = (x – 1)² – (√3)² y = x² – 2x + 1 – 3 y = x² – 2x – 2
How did you find the given examples? Were you able to understand how to derive equations given the graph or zeros of a quadratic function? If not, go back to those parts that you find challenging and study further.
WHAT’S MORE
A. Determine the quadratic function y = ax² + bx + c represented by the given graphs.
[chart: graph of an upward-opening parabola with its lowest point near x = −2, y = 2; grid with x-axis ticks from −5 to 3 and y-axis ticks from 1 to 8; no values are printed beyond the axis ticks]
[chart: graph of an upward-opening parabola with its lowest point near x = 0, y = −3; grid with x-axis ticks from −4 to 4 and y-axis ticks from 6 to −4; no values are printed beyond the axis ticks]
B. Determine the quadratic function given the following zeroes:
- 2, -3 11. ±√3
- 5, 7 12. 2 – √3
- -1, -4 13. 1 + √5
- 6, -5 14. -3 + √2
- 8, 1 15. -4 – √7
- 1/2, 2
- 5, −1/3
- 1/4, 3/4
- 3/5, −1/5
- −3/4, 4/3
How did you find the activity? Did you get all the equations of quadratic functions from the graphs and zeros? If not, in which part did you find challenging? How did you cope up with it?
WHAT I HAVE LEARNED
- If the graphs representing quadratic function y = ax² + bx + c is given, the equation representing the graph can be determined given any of the following conditions:
a. Three points on the parabola, not x-intercepts nor vertex
b. The x-intercepts and a point on the parabola, if coordinates a vertex are not integral
c. A vertex and a point of the parabola - The zeroes, x₁ and x₂, of the function are the roots, of the equivalent quadratic equation. That is,
y = (x – x₁) (x – x₂) → 0 = (x – x₁) (x – x₂)
Now that you are equipped with knowledge on determining the equation of quadratic function given graphs and zeros, it’s about time to find out what you can do.
WHAT I CAN DO
Critical Thinking
A. Determine the quadratic function y = ax² + bx + c represented by the given graphs
- [chart: parabola graph opening upward; item 1 of WHAT I CAN DO]
- [chart: parabola graph opening downward; item 2 of WHAT I CAN DO]
- [chart: parabola graph opening upward; item 3 of WHAT I CAN DO]
- [chart: parabola graph opening downward; item 4 of WHAT I CAN DO]
[transcriber’s note: the graphs have axes and grid lines but no printed values, so no coordinates are given for them]
- [chart: parabola graph opening upward; item 5 of WHAT I CAN DO]
- [chart: parabola graph opening upward; item 6 of WHAT I CAN DO]
B. Determine the quadratic function given the following zeroes:
- 5, 8 6. 2/3, −1/6
- -2, 7 7. ±√5
- 11, -4 8. 1 ± √2
- 3/2, 1 9. -2 ±3√3
- 1/2, 3/2 10. (3 ± √17)/4
ASSESSMENT
Read each item carefully. Identify the choice that best completes the statement or answers the question
What do you call the graph of the quadratic function?
A) Circle B) Hyperbola C) Line D) ParabolaWhat are the zeros of the quadratic function = 2𝑥² − 7𝑥 + 3 ?
A) – 3 & –1/2 B) – 3 & 1/2 C) –1/2 & 3 D) 1/2 & 3Which quadratic function has no zeros?
A) 𝑦 = 𝑥² − 4 C) 𝑦 = −𝑥² + 4
B) 𝑦 = −𝑥² − 4 D) 𝑦 = 𝑥² + 4𝑥
For items 4 – 7, refer to the graph at the right.
- What is the vertex of the graph?
A) (0, –1)
B) (0, 1)
C) (– 1. 0)
D) (1, 0)
[chart: parabola graph opening downward with vertex near the origin; referenced by items 4–7]
How many zero(s) does the graph have?
A) 0 B) 1 C) 2 D) NoneWhat is the range of the graph?
A) (–∞, 0) B) (–∞, 0] C) (0, ∞) D) [0, ∞)Which equation define the given graph?
A) 𝑦 = −𝑥² − 2𝑥 − 1 C) 𝑦 = −𝑥² + 2𝑥 − 1
B) 𝑦 = −𝑥² − 2𝑥 + 1 D) 𝑦 = −𝑥² + 2𝑥 + 1What quadratic function that passes the point (2, 1) and to its only zero of 3?
A) 𝑦 = 𝑥² − 6𝑥 − 9 C) 𝑦 = 𝑥² − 6𝑥 + 9
B) 𝑦 = 𝑥² + 6𝑥 − 9 D) 𝑦 = 𝑥² + 6𝑥 + 9Which of the following equations of the quadratic function that doesn’t cross the x-axis and passes through the point (1, 4).
A) 𝑦 = 𝑥² − 2𝑥 + 5 C) 𝑦 = 3𝑥² − 5𝑥
B) 𝑦 = 2𝑥² − 3𝑥 + 1 D) 𝑦 = 𝑥² + 2𝑥 − 5What quadratic function contain the points (–5, 0), (0, 0) and (2, 14)?
A) 𝑦 = −𝑥² − 5𝑥 C) 𝑦 = 𝑥² − 5𝑥
B) 𝑦 = −𝑥² + 5𝑥 D) 𝑦 = 𝑥² + 5𝑥
ADDITIONAL ACTIVITIES
Communication, Critical Thinking, Creativity and Character Building
Activity 1: Parabola Around Us
There are a lot of objects around us that looks like a parabola like the architectural design of Mactan Cebu international airport.
For this activity, you will explore the rich arts and architectures of the Philippines that have parabolic design.
[photo: interior of an airport terminal with a curved, arched roof of glass and steel]
- Find an example of a real parabolic curve found in the Philippines
- Research about its origin and its actual size.
- Using any graphing applications (android apps, internet app, computer software, and a like), insert the picture into the rectangular plane and adjust the scale to its actual size.
- Insert a point for the vertex of your picture and determine its coordinates.
- Locate for additional points that your graph pass through. Determine the coordinates of this points.
- Using these points, find the equation in general form of the parabola formed by your picture.
PROBLEM – BASED WORKSHEET
A soccer player passes the ball to a teammate, and the teammate kicks the ball. The graph displays the relation of the height in feet of the ball, in feet, t seconds after it is kicked.
[chart: parabola graph of height of the ball; horizontal axis -1, -0.5, O, 0.5, 1, 1.5, 2; vertical axis labeled y with values 5, 6, 7, 8 marked; a soccer player and ball are drawn beside the curve]
Let’s Analyze!
- What is the maximum height that the ball could reach?
- After how many seconds did the ball reached the maximum height?
- Determine the function h(t) from the given graph.
E-Search
You may also check the following link for your reference and further learnings on determining quadratic function given table of values.
- https://www.youtube.com/watch?v=jLzkaJk0iZ0
- https://www.youtube.com/watch?v=vAPPYoBV2Ow
- https://www.youtube.com/watch?v=OXViZtD2BTE
- https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadraticfunctions-equations/x2f8bb11595b61c86:quadratic-formsfeatures/e/rewriting-expressions-to-reveal-information
REFERENCES
MacKeague, Charles, Intermediate Algebra, Concepts and Graphs. Saunders College Publishing, USA
Mathematics 9 Learner’s Material, Department of Education
Ogena, Ester, et. al. Our Math Grade 9. Mc Graw Hill, Vibal Group. Inc
https://www.radford.edu/rumath-smpdc/Performance/src/Leslie%20Cumbow%20-%20Discovering%20Quadratics.pdf
Illustrations:
https://www.freepik.com/free-vector/woman-with-long-hair-teachingonline_7707557.htm https://www.freepik.com/free-vector/kids-having-online-lessons_7560046.htm https://www.freepik.com/free-vector/illustration-with-kids-taking-lessons-onlinedesign_7574030.htm http://www.usccg.com/tag/quality-control/ http://www.erpbusinessschool.lk/programmes/professional-diploma-in-enterpriseresource-planning/careers_chemd_guygirllab_0/ https://www.dezeen.com/2018/12/03/mactan-cebu-international-airportphilippines-integrated-design-associates/
[transcriber’s note: this page is printed upside down; it was read by rotating it. Readings marked [?] are uncertain]
ANSWER KEY
WHAT I KNOW
- D 2. C 3. B 4. C 5. A 6. A 7. A 8. C 9. B 10. C
WHAT’S IN
- -2, 1 2. -1, 3 3. -3, 1 4. -1 5. none 6. none
WHAT’S MORE
A.
- y = x² + 4x + 6
- y = x² − x − 2
- y = x² − 6x + 7 [?]
- y = x² + 2x + 1
- y = 2x² − 4x + 4 [?]
- y = x² − 2x + 2 [?]
B.
- y = x² + x − 6
- y = x² − 12x + 35
- y = x² + 5x + 4
- y = x² − x − 30
- y = x² − 9x + 8
- y = 2x² − 5x + 2
- y = 3x² − 14x − 5
- y = 9x² − 16x + 3 [?]
- y = 25x² − 10x − 3
- y = 12x² − 7x − 12
- y = x² − 3
- y = x² − 4x + 1
- y = x² − 2x − 4
- y = x² + 6x + 7
- y = x² + 8x + 9
WHAT I CAN DO
A.
- y = −x² − 6x + 11 [?]
- [illegible]
- [illegible]
- [illegible]
- [illegible]
- [illegible]
B.
- y = x² − 13x + 40 [?]
- y = x² − 5x − 14 [?]
- y = x² − 7x − 44 [?]
- [illegible]
- [illegible]
- [illegible]
- [illegible]
- [illegible]
ASSESSMENT
- D 2. D [?] 3. B 4. B [?] 5. B [?] 6. D [?] 7. C [?] 8. C [?] 9. A [?] 10. D [?]
ADDITIONAL ACTIVITIES
Use this rubric for checking your output.
[table: RUBRIC FOR ACTIVITY]
| Element | 0 | 1 | 2 |
|---|---|---|---|
| Picture is of a parabola | No picture is turned in | Picture is of a parabola | Picture is of a parabola |
| Dimensions of parabola are noted | No dimensions given | Dimensions given incorrectly | Dimensions of parabola are noted |
| Picture is inserted into graph | No picture inserted | N/A | Picture inserted correctly |
| Vertex and second point are identified | Points are not correctly identified | One point is correctly identified | Both points are identified correctly |
| Equation in vertex form is computed | Equation is not done | Equation is computed with error | Equation is computed correctly |
PROBLEM – BASED WORKSHEET
- 8 ft
- After 0.5 second of ½ second
- h(t) = −16t² + 16t + 4
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