This is the Grade 8 Mathematics Quarter 4 Module 4 self-learning module, Proving Properties of Parallel Lines Cut by a Transversal. It was developed by DepEd Caraga Region (First Edition, 2020) for learners studying at home through the Alternative Delivery Mode. After working through it, learners can name the angle pairs formed when a transversal cuts two parallel lines, use their properties to find missing angle measures, and write simple two-column proofs.
What learners will learn
The module covers the competency on proving properties of parallel lines cut by a transversal (M8GE-IVd-1). After going through it, learners are expected to:
- identify the different angle pairs if parallel lines are cut by a transversal;
- determine the properties of parallel lines when cut by a transversal;
- find the measures of angles using the properties of parallel lines cut by a transversal;
- prove properties of parallel lines that are cut by a transversal; and
- relate real-life problems involving parallel lines cut by a transversal.
Key terms and the parallel postulate
The module opens with everyday examples of parallel lines: pedestrian lanes, the sails of a vinta, the edges of a sheet of paper, and library shelves. It then reviews the types of lines:
- Intersecting lines share a common point.
- Parallel lines are coplanar lines that do not intersect. The symbol ∥ means “is parallel to,” and arrow marks in a diagram show that lines are parallel.
- Perpendicular lines intersect and form right angles.
- Skew lines are not coplanar and do not intersect.
- A transversal is a line that intersects two or more coplanar lines at two or more distinct points.
The Parallel Postulate states that if there is a line and a point not on the line, then there is exactly one line through the point that is parallel to the given line.
Angle pairs and their properties
When two parallel lines are cut by a transversal, eight angles are formed. The module explains each angle pair and the postulate or theorem that goes with it:
| Angle pair | What it is | Property |
|---|---|---|
| Alternate interior angles | Two nonadjacent interior angles on opposite sides of the transversal | Congruent (Parallel-Alternate Interior Angle Postulate) |
| Alternate exterior angles | Two nonadjacent exterior angles on opposite sides of the transversal | Congruent (Parallel-Alternate Exterior Angle Theorem) |
| Corresponding angles | Two nonadjacent angles, one interior and one exterior, on the same side of the transversal | Congruent (Parallel-Corresponding Angles Theorem) |
| Vertical angles | Nonadjacent angles formed by two intersecting lines | Congruent (Vertical Angle Theorem) |
| Interior angles on the same side | Interior angles on the same side of the transversal | Supplementary, sum is 180° (Parallel-Interior Angle-Same Side Theorem) |
| Exterior angles on the same side | Exterior angles on the same side of the transversal | Supplementary, sum is 180° (Parallel-Exterior Angle-Same Side Theorem) |
Congruent angles have equal measures, so each congruence can also be written as an equation, such as m∠A = m∠q.
Worked examples in the module
The lesson uses a zip line at Molave Farm in San Agustin, Surigao del Sur. The two tower posts are the parallel lines, and the cable is the transversal. The module solves four examples:
- Example 1 is a two-column proof that ∠1 ≅ ∠2. It uses vertical angles, the Parallel-Alternate Interior Angle Postulate, and the Transitive Property of Congruence.
- Example 2 sets corresponding angles equal: (6x − 46°) = (5x − 24°), so x = 22°. Each angle then measures 86°.
- Example 3 uses alternate interior angles: 115° = 75° + x, so x = 40°.
- Example 4 returns to the zip line. The interior angles on the same side add up to 180°: (16a − 96°) + (94° − 2a) = 180°, so a = 13°. That gives m∠A = 112° and m∠M = 68°. In the same way, b = 48°, so m∠F = 110° and m∠E = 70°.
The main skill is this: decide which angle pair you have, then either set the two measures equal (congruent pairs) or set their sum to 180° (same-side pairs). Then solve for the variable.
How to use this module
The module follows the usual self-learning module parts, in this order:
- What I Know: a 15-item pretest.
- What’s In: a jumbled-letters review of line types and a city road map.
- What’s New: a stick or straw activity and the zip line problem.
- What is It: the lesson discussion and examples.
- What’s More: practice in naming angle pairs, completing proofs, and finding angle measures.
- What I Have Learned: always/sometimes/never-true items and true-or-false items.
- What I Can Do: a real-life problem about a wheelchair ramp railing.
- Assessment: a 15-item post-test.
- Additional Activities: writing proofs.
- Answer Key.
For learners: Write your answers on a separate sheet of paper and do not mark the module. Check your work with the answer key only after you finish each part, and be honest when you use it. Ask your teacher or facilitator if you have difficulty.
For parents: For Activity 1 in What’s New, your child needs sticks or straws measuring 8, 10, and 12 inches. A broom stick cut to these lengths also works.
For teachers: Use the pretest to see whether a learner needs extra help before starting. Use the post-test to check mastery of competency M8GE-IVd-1.
Frequently asked questions
What grade and quarter is this module for?
It is Grade 8 Mathematics, Quarter 4, Module 4. It covers the competency M8GE-IVd-1, proving properties of parallel lines cut by a transversal.
What is a transversal?
A transversal is a line that intersects two or more coplanar lines at two or more distinct points. In the module’s zip line example, the cable crossing the two parallel posts is the transversal.
Which angle pairs are congruent when parallel lines are cut by a transversal?
Alternate interior angles, alternate exterior angles, corresponding angles, and vertical angles are congruent. Interior angles on the same side and exterior angles on the same side are supplementary, which means their measures add up to 180°.
Does the module have an answer key?
Yes. The answer key covers the pretest, the activities, the post-test assessment, and the additional activities. Learners are asked to use it honestly.
What materials are needed for the activities?
Activity 1 in What’s New needs broom sticks or straws measuring 8, 10, and 12 inches. The other exercises only need a separate sheet of paper for the answers.
Full text of the module
The text below is a transcription of the PDF above, as printed.
Mathematics
Quarter 4 – Module 4
Proving Properties of Parallel Lines Cut by a Transversal
[illustration: teachers and learners studying outdoors and at a table with a globe and a lamp]
Mathematics – Grade 8 Alternative Delivery Mode Quarter 4–Module 4 Proving Properties of Parallel Lines Cut by a Transversal First Edition, 2020
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Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio
Printed in the Philippines by ________________________
Development Team of the Module
Writer: Ruth Ann Maglasang Language Editor: Victorino S. Nimes Content Evaluators: Victorino S. Nimes, Myracell P. Buenaflor, Marie Grace O. Aparre, Ella C. Armayan Layout Evaluator: Devina P. Malinao Reviewers: Rhea J. Yparraguirre, Severiano D. Casil, Alma R. Velasco and Crisante D. Cresino Illustrators: Ruth Ann Maglasang, Fritch A. Paronda, Andy B. Cuadra, and Jefthy L. Olayon Layout Artist: Ruth Ann Maglasang Management Team: Francis Cesar B. Bringas, Isidro M. Biol, Jr., Maripaz F. Magno, Josephine Chonie M. Obseñares, Josita B. Carmen, Celsa A. Casa, Regina Euann A. Puerto, Bryan L. Arreo, Elnie Anthony P. Barcena, Leopardo P. Cortes, Jr., Claire Ann P. Gonzaga
Printed in the Philippines by ________________________
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8
Mathematics
Quarter 4 – Module 4
Proving Properties of Parallel Lines Cut by a Transversal
Introductory Message
This Self-Learning Module (SLM) is prepared so that you, our dear learners, can continue your studies and learn while at home. Activities, questions, directions, exercises, and discussions are carefully stated for you to understand each lesson.
Each SLM is composed of different parts. Each part shall guide you step-by-step as you discover and understand the lesson prepared for you.
Pre-tests are provided to measure your prior knowledge on lessons in each SLM. This will tell you if you need to proceed on completing this module or if you need to ask your facilitator or your teacher’s assistance for better understanding of the lesson. At the end of each module, you need to answer the post-test to self-check your learning. Answer keys are provided for each activity and test. We trust that you will be honest in using these.
In addition to the material in the main text, Notes to the Teacher are also provided to our facilitators and parents for strategies and reminders on how they can best help you on your home-based learning.
Please use this module with care. Do not put unnecessary marks on any part of this SLM. Use a separate sheet of paper in answering the exercises and tests. And read the instructions carefully before performing each task.
If you have any questions in using this SLM or any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator.
Thank you.
What I Need to Know
[illustration: hand pressing a touch point inside a circle]
This module was designed and written with you in mind. It will help you to learn the properties of parallel lines. This guides you in discovering the postulates and theorems of parallel lines. Moreover, it introduces the idea of angle pairs when two parallel lines are cut by a transversal line. The lessons are arranged to follow the standard sequence of the course. But the order in which you read them can be changed to correspond with the textbook you are now using.
This module contains lesson on proving properties of parallel lines cut by a transversal (M8GE-IVd-1).
After going through this module, you are expected to:
- identify the different angle pairs if parallel lines are cut by a transversal,
- determine the properties of parallel lines when cut by a transversal,
- find the measures of angles using the properties of parallel lines cut by a transversal,
- prove properties of parallel lines that are cut by a transversal, and
- relate real-life problems involving parallel lines cut by a transversal.
What I Know
[illustration: hand holding a pencil inside a circle]
Directions: Answer each of the following items. Write the letter of the correct answer on a separate sheet of paper.
What can be said about the alternate interior angles if two parallel lines are cut by a transversal?
- A. complementary
- C. parallel
- B. congruent
- D. perpendicular
What do you call those two coplanar lines that do not intersect?
- A. congruent
- C. perpendicular
- B. parallel
- D. supplementary
For items 3 – 4, refer to Figure 1 below. e ∥ f and d is a transversal line.
[chart: diagram; Figure 1] Labels: e; f; d; 1, 2, 3, 4, 5, 6, 7, 8
Which of the following are corresponding angles?
- A. ∠1 and ∠8, ∠2 and ∠3
- B. ∠2 and ∠7, ∠1 and ∠6
- C. ∠4 and ∠8, ∠1 and ∠8
- D. ∠5 and ∠3, ∠2 and ∠8
Which of the following statements is NOT correct?
- A. ∠2 and ∠3 are congruent.
- B. ∠3 and ∠8 form a linear pair.
- C. ∠4 and ∠7 are congruent angles.
- D. ∠5 and ∠6 are supplementary angles.
For items 5 – 9, refer to the figure at the right. Given: u ∥ v and w is a transversal line.
[chart: diagram; figure for items 5 – 9 (no title printed)] Labels: u; v; w; 1, 2, 3, 4, 5, 6, 7, 8
Which of the following could be the reason to prove that ∠1 ≅ ∠4?
- A. Vertical angles are congruent.
- B. Corresponding angles are congruent.
- C. Supplementary angles are congruent.
- D. Alternate interior angles are congruent.
Which of the following could be the reason to prove that ∠2 ≅ ∠7?
A. Vertical angles are congruent.
B. Corresponding angles are congruent.
C. Alternate exterior angles are congruent.
D. Alternate interior angles are congruent.
Which of the following statements is justified by the reason, “same side interior angles are supplementary?”
- A. m∠4 + m∠7 = 180°
- C. m∠4 + m∠6 = 180°
- B. m∠5 + m∠8 = 180°
- D. m∠2 + m∠7 = 180°
What would be the reason to prove that ∠3 ≅ ∠7?
- A. Vertical angles are congruent.
- B. Corresponding angles are congruent.
- C. Alternate interior angles are congruent.
- D. Alternate exterior angles are congruent.
In a two-column proof, “vertical angles are congruent” is written under the reason column. Which of the following is appropriate to write under the statement column?
- A. ∠5 ≅ ∠8
- C. ∠1 ≅ ∠8
- B. ∠4 ≅ ∠3
- D. ∠3 ≅ ∠6
For items 10 – 11, refer to the figure at the right. Given: x ∥ y and z is a transversal line.
[chart: diagram; figure for items 10 – 11 (no title printed)] Labels: x; y; z; a; b; c; d
If m∠a = 99°, what is the measure of ∠d?
- A. 45°
- C. 90°
- B. 81°
- D. 99°
Rona was asked by her teacher to find the value of y given that m∠a = 6y and m∠c = 13y − 10°. She wrote her computation in this way:
(6y) + (13y − 10°) = 180° 19y − 10° + 10° = 180° + 10° 19y = 190° y = 10°
Did she arrive at the correct answer?
- A. Yes. Common variables must be combined.
- B. No. The equation must be (6y) = (13y − 10).
- C. No. Multiplying both sides of the equation by 1/19 is not equal to y = 10.
- D. Yes. The equation she formulated is correct since ∠a and ∠c are supplementary angles.
What I Know (continued)
For items 12 – 13, please refer to the situation below and the figure at the right.
Peter, James, and John were practicing archery. One day, they decided to play the target with their arrow. The figure at the right shows the orientations of their arrows. Arrow c is Peter’s arrow, arrow d is James’, and arrow e is John’s. Peter’s and James’ arrows are parallel to each other while John’s cut the other two. The angle formed by Peter’s and John’s arrows denoted by ∠a is 12x + 3°, James’ and John’s denoted by ∠b is 11x + 9°, and the other angle formed by James’ and John’s arrows is 18x − 3°.
[illustration: archery target with three arrows; printed labels (12x + 3°), a, (11x + 9°), b, (18x − 3°), c, d, e]
- Which of the following shows the mathematical equation of the measures of corresponding angles?
- A. 12x + 3° = 11x + 9°
- B. 12x + 3° + 11x + 9° = 180°
- C. 12x + 3° + 18x − 3° = 180°
- D. 12x + 3° = 18x − 3°
- A Grade 8 student wanted to find the value of x in the situation. His computation is as follows:
(12x + 3°) + (11x + 9°) = 180° (12x + 11x) + (3° + 9°) = 180° 23x + 12° − 12° = 180° − 12° 23x = 168° x = 7.30°
Is his computation correct?
- A. Yes. Common terms must be combined.
- B. Yes. The value x = 7.30° gives the measure of ∠a as 90.6°.
- C. No. The equation should be (12x + 3°) + (18x − 3°) = 180°, since they are alternate angles.
- D. No. The equation should be (12x + 3°) = (11x + 9°), since they are corresponding angles.
For items 14 – 15, complete the proof presented in the table below by choosing the answer from any of the following statements or reasons:
- A. m∠1 ≅ m∠3
- B. Transitive Property of Congruence
- C. Substitution Property of Equality
- D. m∠2 + m∠3 = 180°
[chart: diagram; figure for items 14 – 15 (no title printed)] Labels: h; t; k; 1; 2; 3
[transcriber’s note: the proof table referred to in items 14 – 15 does not appear on this page; it is not transcribed here]
In the figure above, h ∥ t and k is a transversal of h and t. Prove that m∠1 + m∠2 = 180°.
Proof:
| Statements | Reasons |
|---|---|
| 1. h ∥ t, k is a transversal of h and t | 1. Given |
| 2. ∠1 ≅ ∠3 | 2. Parallel – Corresponding Angles Theorem |
| 3. m∠1 = m∠3 | 3. Congruent angles have the same measure. |
| 4. (14) | 4. Linear Pair Theorem |
| 5. m∠1 + m∠2 = 180°. | 5. (15) |
Lesson 1: Proving Properties of Parallel Lines Cut by a Transversal
When crossing the street, have you noticed the lines used on pedestrian lanes? How about in designing vintas? Imagine that you are in the bustling city and you have been standing in the middle of tall buildings and magnificent skyscrapers. Have you ever wondered how the architects, engineers and carpenters made these designs? How are parallel lines applied in these designs?
We know that parallel lines exist everywhere in our everyday lives like on the edges of a piece of paper and in the way shelves of books are positioned in a library. The concept of parallel lines is a key component of geometry that is applied in real life in designs and structures.
[illustration: a pedestrian lane with a striped crossing on a street] A pedestrian lane
[illustration: a vinta sailing boat with triangular sails] A vinta
This lesson culminates with various activities such as solving real-life situations and proving properties of parallel lines.
What’s In
Activity: Arrange Me!
You have learned in the previous quarter the different properties and theorems of angles. This time, let us check your prior knowledge on the types of lines. This activity encourages you to remember the terms your learned from the previous lessons.
A. Directions: Arrange the jumbled letters to form a word.
- Two lines that share a common point.
G N T C I T E N R I E S - Two coplanar lines that do not intersect.
A L L A P E R L - These are lines that lie on the same plane.
C A P R O A L N - Two lines that intersect and form right angles.
P R E P D E N L I U R A C - Two lines that are not coplanar and do not intersect.
E W S K - A line that intersects two or more coplanar lines at two or more distinct points.
R A N T S S V E L A R
B. Road Map! Below is the road map of the city of San Juaquin.
[chart: road map of the city of San Juaquin; B. Road Map!] Labels as printed: Poblacion; Mabini Street; St. Louis Subdivision; Public Hospital; Mac Arthur Highway; Bonifacio Intersection; Municipality Hall; Andres Avenue; Malvar Village; Police Station.
Questions:
- Which roads intersect?
- Which roads are parallel?
- Which roads are perpendicular?
What’s New
Let us now begin discovering the world of parallel lines, uncover its properties and how they play an important role in our daily lives. Read and do the tasks that follow.
Activity 1: Uncover Me!
Directions: Perform the simple activity and answer the questions that follow.
Materials needed:
- Broom Stick or Straws measuring 8 inches, 10 inches and 12 inches
Steps:
- Get the sticks or straws measuring 8 and 10 inches.
- Position the sticks or straws horizontally (8-inch stick above the 10-inch stick).
- Place the remaining 12-inch stick or straw on top of the two horizontal sticks in slant position so that it intersects the two lines at two different points.
Questions:
- How was the activity?
- What was the activity about?
- Did you find any difficulty/ies in performing the task given to you? Please write them.
- How would you describe the lines formed?
- Do these lines meet or intersect?
- Are these lines parallel? Why or why not?
- How many angles are formed after the transversal cut the parallel lines?
Activity 2: Try Me
Study the situation below and answer the questions that follow:
Mario is an owner of Molave Farm found in San Agustin, Surigao del Sur in which one of his offered rides to the public is a zip line. A zip line is a very strong cable between two points with a pulley attached to it. The zip line as illustrated in the figure below goes from a 25-foot tall tower, represented by c to a 20-foot tower as d and it is 200 meters apart in a slightly inclined ground.
[chart: diagram of parallel posts c and d cut by transversal AM, with ground line FE; labels: x, y, z, A, (16a – 96°), q, r, M, (94 – 2a°), s, c, d, (3b – 34°), F, (b + 22°), E]
Questions:
If the two posts which are represented by lines c and d, respectively, are parallel, what do you call the strong cable which is represented by line AM?
If lines c and d are extended to form other angles, name the following:
a. two pairs of alternate-interior angles;
b. two pairs of alternate-exterior angles;
c. four pairs of corresponding angles;
d. two pairs of same-side interior angles;
e. two pairs of same-side exterior angles; and
f. four pairs of vertical angles.Do you think ∠A and ∠q are congruent angles?
What about ∠M and ∠r, are they congruent?
What about ∠x and ∠s, are they congruent?
Using the information in the figure above, find the measures of the following angles:
a. ∠A c. ∠F
b. ∠M d. ∠E(Hint: To get the measure of those angles, first, find the values of a and b, then use them in the equation).
If you add m∠A and m∠M, what is their sum?
If you add m∠F and m∠E, what is their sum?
What is It
The results of the activity above lead you to the following properties of parallel lines cut by a transversal, as well as theorems and postulates on parallel lines.
Properties, Theorems and Postulates on Parallel lines cut by a Transversal:
A. Parallel Postulates: If there is a line and a point not on the line, then there is exactly one line through the point that is parallel to the given line.
[chart: diagram of lines s and m, with transversals q and t meeting at point P; labels: q, t, P, s, m]
Given a line m and a point P not in m, there is only one line (line s) that is parallel to line m passing through point P. In symbol, s ∥ m (read as, line s is parallel to line m). Lines t and q are not parallel to line m through P.
Also, two or more lines are parallel if you find the symbols like the ones illustrated below.
[illustration: two parallel horizontal lines, each with matching arrow marks; a rectangle with arrow marks on pairs of opposite sides]
s ∥ m is read as “line s is parallel to line m.” In geometry, the term parallel is denoted by ∥ which means “is parallel to”. Also, an arrow is used in diagrams to indicate that lines are parallel. Moreover, the term parallel is used for lines, segments, rays, and planes.
Going back to the situation about the zip line, the two posts where the cable is connected, represented by line c and line d, are the two parallel lines (c ∥ d), and the cable which is represented by line AM is called the transversal. The imaginary line FE that is drawn with the ground is also considered transversal line since it cuts the two posts at distinct points.
[chart: diagram of parallel posts c and d cut by transversal AM, with ground line FE; labels: x, y, z, A, (16a – 96°), q, r, M, (94 – 2a°), s, c, d, (3b – 34°), F, (b + 22°), E]
A transversal is a line that intersects two or more coplanar lines at two or more distinct points.
B. Angles Formed by Parallel Lines Cut by a Transversal
Definition: Alternate Interior Angles – are two nonadjacent interior angles on opposite sides of the transversal.
Parallel-Alternate Interior Angle Postulate
If two parallel lines are cut by a transversal, then any pair of alternate interior angles are congruent.
In the figure above, the pairs of alternate interior angles are ∠A & ∠q and ∠y & ∠M. By the postulate, ∠A ≅ ∠q and ∠y ≅ ∠M. Since they are congruent, their measures are equal (m∠A = m∠q and m∠y = m∠M).
Definition: Alternate Exterior Angles – are two nonadjacent exterior angles on opposite sides of a transversal.
Parallel-Alternate Exterior Angle Theorem
If two parallel lines are cut by a transversal, then any pair of alternate exterior angles are congruent.
In the same figure, the pairs of alternate exterior angles are ∠z & ∠r and ∠x & ∠s. By the theorem, ∠z ≅ ∠r and ∠x ≅ ∠s. Since they are congruent, their measures are equal (m∠z = m∠r and m∠x = m∠s).
Definition: Corresponding Angles – are two nonadjacent angles, one interior, and one exterior on the same side of the transversal.
Parallel-Corresponding Angles Theorem
If two parallel lines are cut by a transversal, then the corresponding angles are congruent.
In the same figure, the four pairs of corresponding angles are ∠z & ∠M, ∠A & ∠s, ∠x & ∠q, and ∠y & ∠r. By the theorem, ∠z ≅ ∠M, ∠A ≅ ∠s, ∠x ≅ ∠q, and ∠y ≅ ∠r. Since they are congruent, their measures are equal (m∠z = m∠M, m∠A = m∠S, m∠x = m∠q, and m∠y = m∠r).
Definition: Vertical Angles – Two angles are vertical angles if and only if they are nonadjacent angles formed by two intersecting lines.
Vertical Angle Theorem
Vertical angles are congruent.
In the same figure, the four pairs of vertical angles are ∠x & ∠A, ∠z & ∠y, ∠q & ∠s, and ∠M & ∠r. By the theorem, ∠x ≅ ∠A, ∠z ≅ ∠y, ∠q ≅ ∠s, and ∠M ≅ ∠r. Since they are congruent, their measures are equal (m∠x = m∠A, m∠z = m ∠y, m∠q = m∠s, and m∠M = m∠r).
Parallel-Interior Angle-Same Side Theorem
If two parallel lines are cut by a transversal, then the interior angles on the same side of the transversal are supplementary.
In the same figure, the pairs of interior angles on the same side of the transversal are ∠A & ∠M and ∠y & ∠q. Along the ground, the pair of interior angles on the same side of the transversal is ∠F & ∠E. By the theorem, these pairs of angles are supplementary, hence, m∠A + m∠M = 180°, and m∠y + m∠q = 180°. Also, m∠F + m∠E = 180°.
Parallel-Exterior Angle-Same Side Theorem
If two parallel lines are cut by a transversal, then the exterior angles on the same side of the transversal are supplementary.
In the same figure, the pairs of exterior angles on the same side of the transversal are ∠z & ∠s and ∠x & ∠r. By the theorem, these pairs of angles are supplementary, hence, m∠z + m∠s = 180°, and m∠x + m∠r = 180°.
The table below sums up the properties, postulates and theorems of the angles formed by parallel lines c and d cut by a transversal line AM.
[transcriber’s note: the header cell “Properties, Postulate, Theorems” spans the last three columns of the table]
| Angles Formed | Pair of Angles | Congruent angles | Equal angles |
|---|---|---|---|
| Alternate Interior Angles | Pair of Angles: ∠A and ∠q ∠y and ∠M | ∠A ≅ ∠q ∠y ≅ ∠M | m∠A = m∠q m∠y = m∠M |
| Alternate Exterior Angles | Pair of Angles: ∠z and ∠r ∠x and ∠s | ∠z ≅ ∠r ∠x ≅ ∠s | m∠z = m∠r m∠x = m∠s |
| Corresponding Angles | Pair of Angles: ∠z and ∠M ∠A and ∠s ∠x and ∠q ∠y and ∠r | ∠z ≅ ∠M ∠A ≅ ∠s ∠x ≅ ∠q ∠y ≅ ∠r | m∠z = m∠M m∠A = m∠s m∠x = m∠q m∠y = m∠r |
| Vertical Angles | Pair of Angles: ∠x and ∠A ∠z and ∠y ∠q and ∠s ∠M and ∠r | ∠x ≅ ∠A ∠z ≅ ∠y ∠q ≅ ∠s ∠M ≅ ∠r | m∠x = m∠A m∠z = m∠y m∠q = m∠s m∠M = m∠r |
Interior Angles on the Same Side of the Transversal is printed as the first row of the table, with no separate header row, so it is used as the header below.
transcriber’s note: the printed table has no separate header row; its first row is used as the header.
| Interior Angles on the Same Side of the Transversal | Pair of Angles: ∠A and ∠M ∠y and ∠q ∠F and ∠E | Supplementary angles: m∠A + m∠M = 180° m∠y + m∠q = 180° m∠F + m∠E = 180° |
|---|---|---|
| Exterior Angles on the Same Side of the Transversal | Pair of Angles: ∠z and ∠s ∠x and ∠r | Supplementary angles: m∠z + m∠s = 180° m∠x + m∠r = 180° |
Now that we know these postulates and theorems, let us take a look at the following examples:
Example 1
Given: n ∥ m, transversal a Prove: ∠1 ≅ ∠2.
[chart: diagram; Example 1 figure, unnumbered. Labels: 1, 2, 3, 4; lines n and m are parallel; transversal a]
Proof:
| Statements | Reasons |
|---|---|
| 1. n ∥ m, transversal a | 1. Given |
| 2. ∠1 ≅ ∠3 | 2. Vertical angles are congruent. |
| 3. ∠3 ≅ ∠4 | 3. Parallel-Alternate Interior Angle Postulate |
| 4. ∠1 ≅ ∠4 | 4. Transitive Property of Congruence |
| 5. ∠4 ≅ ∠2 | 5. Vertical angles are congruent |
| 6. ∠1 ≅ ∠2 | 6. Transitive property of congruence |
Example 2
Given: c ∥ d, transversal a and if m∠1 = (6x − 46°) and m∠4 = (5x − 24°), find the value of x, then solve for the measure of each angle below:
- m∠1
- m∠4
- m∠2
- m∠3
[chart: diagram; Example 2 figure, unnumbered. Labels: 6x − 46°, 5x − 24°, 1, 2, 3, 4; lines c and d are parallel; transversal a]
Solutions:
- To find the measure of ∠1, we must find first the value of x. We know that ∠1 and ∠4 are corresponding angles, and corresponding angles are congruent, hence, their measures are equal. From then, we can now formulate an equation:
m∠1 = m∠4 — Corresponding angles are congruent (6x − 46°) = (5x − 24°) — Substitution 6x − 5x − 46° = 5x − 5x − 24° — Addition Property of Equality, add (-5x) to both sides of the equation x − 46° = −24° — Simplify x − 46° + 46° = −24° + 46° — Addition Property of Equality, add (46) to both sides of the equation x = 22° — Simplifiy
So, x = 22°.
Substitute x by its value in the equation, m∠1 = (6x − 46°), we have:
m∠1 = (6x − 46°) — Equation for m∠1 m∠1 = [6(22°) − 46°] — Substitute x by its value m∠1 = (132° − 46°) — Simplify m∠1 = 86° — Result
m∠4 = (5x − 24°) — Equation for ∠4
m∠4 = [5(22°) − 24°] — Substitute x by its value
m∠4 = (110° − 24°) — Simplify
m∠4 = 86° — Resultm∠2 =?
Answer: m∠2 = 86° Reason: ∠2 and ∠4 are vertical angles, and vertical angles are congruentm∠3 =?
Answer: m∠3 = 86° Reason: ∠2 and ∠3 are corresponding angles, and corresponding angles are congruent, ∠3 and ∠4 are alternate-interior angles and they are congruent, and ∠1 and ∠3 are vertical angles and they are also congruent.
Example 3
In the figure at the right, m ∥ n. What is the value of x?
[chart: diagram; Example 3 figure, unnumbered. Labels: m (top line), n (bottom line), 75°, 115°, x]
Solution:
Given m ∥ n, we get
115° = 75° + x — Alternate interior angles are congruent 115° − 75° = 75° − 75° + x — Addition property 40° = x — Simplify x = 40° — Symmetric property
Example 4
Now, let us revisit our answers to the measures of the angles in Activity 2.
a. m∠A = 16a − 96° b. m∠M = 94° − 2a c. m∠F = 3b − 34° d. m∠E = b + 22°
[chart: diagram; Example 4 figure, unnumbered. Labels: x, y, z, q, r, s, A, M, F, E, (16a − 96)°, (94 − 2a)°, (3b − 34)°, (b + 22)°]
Solution:
We know that ∠A and ∠M are interior angles on the same side of the transversal, therefore, the sum of their measures is 180°. Solving for the value of a, we have:
m∠A + m∠M = 180° 16a − 96° + 94° − 2a = 180° 14a − 2° + 2° = 180° + 2° 14a = 182° a = 13°
a. m∠A = 16a − 96° = 16(13°) − 96° = 208° − 96° = 112°
b. m∠M = 94° − 2a = 94° − 2(13°) = 94° − 26° = 68°
We know that ∠F and ∠E are interior angles on the same side of the transversal, therefore, the sum of their measures is 180°. Solving for the value of b, we have:
m∠F + m∠E = 180° 3b − 34° + b + 22° = 180° 4b − 12° + 12° = 180° + 12° 4b = 192° b = 48°
c. m∠F = 3b − 34° = 3(48°) − 34° = 144° − 34° = 110°
d. m∠E = b + 22° = 48° + 22° = 70°
Now that you have learned the properties, postulate, and theorems on parallel lines cut by a transversal, pack them with you on your journey to the next activity.
[illustration: hand stacking blocks]
What’s More
Activity 1: Fill Me!
Given the figure at the right, x ∥ y, and transversal w
A. Name the following:
- two pairs of alternate interior angles
- four pairs of corresponding angles
- two pairs of same side interior angles
- four pairs of vertical angles
- two pairs of alternate exterior angles
- two pairs of same side exterior angles
B. Complete each statement.
- Any pair of alternate interior angles are ____________.
- Any pair of corresponding angles are _____________.
- Same side exterior angles are ___________.
- Any pair of vertical angles are __________.
[chart: diagram; Activity 1 figure, unnumbered. Labels: w (transversal), x and y (parallel lines), a, b, c, d, e, f, g, h]
Activity 2: Prove It
Given the figure at the right, complete each proof:
- Given: p ∥ q, transversal m
Prove: ∠3 ≅ ∠5
[chart: diagram; Activity 2 figure, unnumbered. Labels: p, q, m, 1 through 8]
Proof:
| Statements | Reasons |
|---|---|
| 1. p ∥ q, transversal m | 1. ____________________ |
| 2. ∠3 ≅ ∠7 | 2. _____________________ |
| 3. _________________ | 3. Vertical Angles are congruent |
| 4. ∠3 ≅ ∠5 | 4. Transitive Property of Congruence |
- Given: p ∥ q, transversal m
Prove: ∠1 ≅ ∠7
Proof:
| Statements | Reasons |
|---|---|
| 1. _______________ | 1. Given |
| 2. ∠1 ≅ ∠3 | 2. _____________________ |
| 3. _______________ | 3. Alternate interior angles are congruent |
| 4. ∠1 ≅ ∠5 | 4. _______________________ |
| 5. ∠5 ≅ ∠7 | 5. Vertical angles are congruent |
| 6. ______________ | 6. ________________________ |
- Given: p ∥ q, transversal m
Prove: ∠2 ≅ ∠6
Proof:
| Statements | Reasons |
|---|---|
| 1. ________________ | 1. Given |
| 2. ________________ | 2. Vertical Angles are congruent |
| 3. ________________ | 3. _____________________ |
| 4. ∠2 ≅ ∠6 | 4. _______________________ |
Activity 3: Find It!
Given the figure at the right such that a ∥ b, and transversal c
[chart: diagram; Activity 3 figure, unnumbered. Labels: a and b (parallel lines), c (transversal), 1 through 8]
A. Find the value of x and the measure of each specified angle.
If m∠2 = 3x + 14° and m∠4 = 2x + 6°, what is
a. m∠2
b. m∠4
c. m∠8
d. m∠6If m∠6 = 2x + 24° and m∠7 = 3x + 12°, what is
a. m∠6
b. m∠7
c. m∠4
d. m∠3
B. Given the figure at the right, OE ∥ PR. Answer the following questions and justify your answer.
- What is the value of x?
- What is the value of y?
- What is the measure of ∠PRO?
[chart: diagram; Activity 3 part B figure, unnumbered. Labels: W, O, x, y, E, 51°, P, 73°, R]
What I Have Learned
Remember Me: Is it True or Not?
A. Directions: Write AT if the statement is always true, ST if the statement is sometimes true, or NT if the statement is never true.
If two parallel lines are cut by a transversal, then
- alternate interior angles are congruent.
- corresponding angles are congruent.
- interior angles on the same side of the transversal are supplementary.
- exterior angles on the same side of the transversal form a linear pair.
- vertical angles are supplementary.
- vertical angles are congruent.
- linear pair are congruent.
- alternate interior angles are supplementary.
- same side exterior angles are congruent.
- same side interior angles are supplementary.
B. Directions: Determine whether the statement is True or False. Write T if the statement is True and F if it is False.
- Through a point not on a line, you can sometimes construct a parallel line.
- Two lines that are parallel to a third line are never parallel.
- Two lines are parallel if they are coplanar and do not intersect.
- Through a point outside a line, there is one and only one line parallel to the given line.
- The shelves of a bookcase are parallel to each other.
- The ceiling and a wall of a room form a linear pair.
- The opposite edges of a book are sometimes parallel.
- The service lines on a tennis court are parallel to each other.
- A line that intersects two skew lines is a transversal.
- The opposite sides of the base of the Great Pyramid of Giza are always parallel with each other.
What I Can Do
Study the situation below and solve for the value of the variables:
Reynante was a polio victim and was using his wheelchair for almost 5 years now. One day, he visits his doctor for his quarterly check-up and he passes by the wheelchair ramp which has a railing.
As shown in the illustration at the right, the railing of the wheelchair ramp is parallel to the ramp and is supported by braces which formed angles given below:
brace A : (4x + 3y)°, and brace B : (2x + 3y)°
Find the value of x and the value of y.
[illustration: man in a wheelchair on a ramp with a railing; angles labeled (4x+3y)°, (2x+3y)°, 100°, and 80°]
| Solution: | Answers: |
|---|---|
| x=_____ | |
| y= _____ |
Assessment
Directions: Answer each of the following items. Write the letter of the correct answer on a separate sheet of paper.
For numbers 1 – 5, refer to the figure at the right.
Given: u ∥ v
[chart: diagram; Assessment items 1–5 figure, unnumbered. Labels: u, v (parallel lines), w (transversal), 1 through 8]
What do you call the line w?
A. Bisector C. Side
B. Base D. Transversal∠1 and ∠8 called _________.
A. Vertical angles C. Alternate exterior angles
B. Corresponding angles D. Alternate interior angles∠6 and ∠2 are called _________.
A. Alternate Exterior Angles C. Corresponding angles
B. Alternate Interior Angles D. Vertical AnglesIf the m∠1 = 40°, what is the measure of ∠7?
A. 40° C. 130°
B. 50° D. 140°Which pair of angles are supplementary?
A. ∠1 and ∠4 C. ∠4 and ∠8
B. ∠3 and ∠5 D. ∠6 and ∠7Which of the following statements is ALWAYS TRUE when parallel lines are cut by a transversal?
A. Corresponding angles are congruent.
B. The vertical angles are always acute.
C. The sum of the measures of alternate interior angles is 180°.
D. Interior angles on the same side of the transversal are congruent.Given two parallel lines cut by a transversal, then a pair of alternate interior angles are ____________.
A. complementary C. parallel
B. congruent D. perpendicularA commercial airplane begins to land at Davao International Airport at an elevation of 36,000 feet and at a distance of 110 miles. What concept is being applied?
A. Skew line C. Perpendicular line
B. Parallel line D. none of the above
For items 9 – 11, refer to the figure at the right. e ∥ f and d as a transversal.
- What is the value of x?
A. 6
B. 5
C. 4
D. 3
[chart: diagram; items 9–11 figure, unnumbered. Labels: e and f (parallel lines), d (transversal), (15x − 35°), 55°, 1, 2, 4, 5, 6, 7]
All of the following statements are true EXCEPT ?
a. ∠6 and ∠7 are congruent.
b. ∠1 and ∠7 form a linear pair.
c. ∠5 and ∠2 are congruent angles.
d. ∠5 and ∠6 are supplementary angles.What could be the measure of ∠6?
a. 55° c. 115°
b. 75° d. 125°
For items 12 – 14, refer to the figure at the right. 𝒄 ∥ 𝒅 and 𝒆 as a transversal.
[illustration: transversal e crossing parallel lines c and d; angle 1 at the upper intersection; labels 7x + 29° and 2x + 104° beside the two angles on the transversal]
Alma was asked by her teacher to find the measure of ∠1. How will she find it?
i. Subtract the value of 7𝑥 + 29° or 2𝑥 + 104° from 180°.
ii. Solve for the value of 𝑥 using the equation (7𝑥 + 29°) + (2𝑥 + 104°) = 180°.
iii. Substitute 𝑥 by its value in 7𝑥 + 29° or 2𝑥 + 104°.
iv. Solve for the value of 𝑥 using the equation (7𝑥 + 29°) = (2𝑥 + 104°).a. iv, ii, iii c. ii, iii, iv
b. iii, iv, i d. iv, iii, iWhat pair of angles are represented by (7𝑥 + 29°) and (2𝑥 + 104°)?
a. Supplementary angles c. Linear pair
b. Corresponding angles d. Vertical anglesTo complete her task, Alma solved for the measure of ∠1 as follows:
(7𝑥 + 29°) = (2𝑥 + 104°)
7𝑥 − 2𝑥 + 29° − 29° = 2𝑥 − 2𝑥 + 104° − 29°
5𝑥 = 75°
𝑥 = 15°
𝑚∠1 = 15°Is she correct?
a. Yes, because she used corresponding angles.
b. Yes, because she followed the steps correctly.
c. No, because the two angles are supplementary.
d. No, because the value of x is not the measure of ∠1.Refer to the figure at the right.
Given: 𝒍 ∥ 𝒎 and 𝒆 is a transversal line.
Prove: ∠3 ≅ ∠7
Choose from the following statements to complete the table of proof.
a. ∠6 ≅ ∠7
b. 𝑚∠3 + 𝑚∠5 = 180°
c. 𝑚∠5 + 𝑚∠7 = 180°
d. ∠2 ≅ ∠7
[illustration: transversal e crossing parallel lines l and m, with angles numbered 1 to 8 at the two intersections]
| Statements | Reasons |
|---|---|
| 1. 𝒍 ∥ 𝒎 | 1. Given |
| 2. ∠3 ≅ ∠6 | 2. Alternate interior angles are congruent |
| 3. _____ (15) | 3. Vertical angles are congruent |
| 4. ∠3 ≅ ∠7 | 4. Transitivity |
Additional Activities
[illustration: hand holding a gear, decorative icon beside the heading]
Prove It!
Directions: Construct a two-column proof to prove the statement below.
- Given: 𝑙₁ ∥ 𝑙₂ and 𝑙₃ is a transversal line
Prove: ∠1 ≅ ∠3.
[illustration: parallel lines l₁ and l₂ cut by transversal l₃; angles 1, 2 and 3 labeled]
- Refer to the given figure below for which 𝑠 ∥ 𝒕, 𝑚 ∥ 𝒑, and 𝑚∠4 = 57°.
[chart: geometric figure; parallel lines s and t cut by transversal m, parallel lines m and p cut by transversal p; angles labeled 1 to 8 and a to h]
a. What is 𝑚∠𝑎? e. What is ∠ℎ?
b. What is 𝑚∠𝑐? f. What is ∠5?
c. What is ∠2? g. What is ∠8?
d. What is ∠7? h. What is ∠𝑓?
Answer Key
[illustration: key icon beside the heading]
transcriber’s note: this page is printed rotated 180 degrees, and the answer-key columns could not be fully recovered in their original arrangement. Entries are given in the order they appear on the page; uncertain pairings are marked [?].
What I Know
B 9. A 1. B 10. B 2. D D 11. 3. B 12. A 4. A 13. D 5. C 14. D 6. C C 15. 7. B 8.
What’s In
A.
- INTERSECTING
- PARALLEL
- COPLANAR
- PERPENDICULAR
- SKEW
- TRANSVERSAL
B.
- Mabini St. & Mac Arthur Highway; Andres Ave. & Mac Arthur Highway; Bonifacio Intersection & Mac Arthur Highway
- Andres Ave. & Bonifacio Intersection; Mabini St. & Bonifacio Intersection
- Mabini St. & Mac Arthur Highway; Andres Ave. & Mac Arthur Highway; Bonifacio Intersection & Mac Arthur Highway
What I Have Learned
A.
- AT
- AT
- AT
- NT
- ST
- AT
- ST
- ST
- ST
- AT
B.
- F
- F
- T
- T
- T
- F
- F
- T
- F
- T
What I Can Do
x = 10 ; y = 20
What’s New
Activity 1: Uncover me!
- Answer varies
- Parallel lines cut out by a transversal
- Answer varies
- The 8 & 10 inches stick/straw represent parallel lines while the remaining stick represents the transversal line.
- Yes
- Yes, 8 & 10 sticks are parallel to each other.
- 8 angles formed
Activity 2: Try me!
- Transversal
- ∠M & ∠y; ∠A & ∠q
a. ∠r & ∠z; ∠s & ∠x
b. ∠s & ∠A; ∠M & ∠z
c. ∠r & ∠y; ∠q & ∠x
d. ∠q & ∠y; ∠M & ∠A
e. ∠s & ∠z; ∠r & ∠x
f. ∠y & ∠z; ∠A & ∠x
g. ∠r & ∠M; ∠s & ∠q - Yes, Alternate interior angles are congruent
- Yes, vertical angles are congruent
- Yes, alternate exterior angles are congruent
- 112° a. / 68° b. / 110° c. / 70° d.
- 180°
- 180°
Assessment
- D
- C
- C
- D
- B
- A
- B
- B
- A
- B
- D
- D
- B
- D
- A
What’s More
Activity 1: Fill me!
A.
- ∠d & ∠f; ∠e & ∠c; ∠b & ∠h; ∠a & ∠g
- ∠a & ∠f; ∠e & ∠h; ∠b & ∠f; ∠c & ∠g
- Answer varies
- ∠a & ∠c; ∠b & ∠d; ∠e & ∠g; ∠f & ∠h
- ∠a & ∠g; ∠b & ∠h
- ∠a & ∠g; ∠b & ∠h
B. 7. Congruent 8. Congruent 9. Supplementary 10. Congruent
Activity 2: Prove It!
- Statement / Reason
1.1. Given
1.2. Corresponding angles are congruent
1.3. ∠5 ≅ ∠7 - 𝑚 ∥ 𝑛, transversal 𝑞 ∥ 𝑝
2.1. Vertical angles are congruent
2.2. ∠5 ≅ ∠3
2.3. Corresponding angles are congruent
2.4. ∠7 ≅ ∠1
2.5. Statement: ∠3 ≅ ∠1
2.6. Reason: Transitive Property of Congruence - 𝑚 ∥ 𝑛, transversal 𝑞 ∥ 𝑝
3.1. ∠4 ≅ ∠2
3.2. ∠6 ≅ ∠4
3.3. Statement: ∠6 ≅ ∠2; Reason: Alternate interior angles are congruent
3.4. Transitive Property of Congruence
Activity 3
- A. x = 32°; A1. x = 32°; A2. x = 12°
B. 112° a. / 68° b. / 68° c. / 112° d. / 48° a. / 48° b. / 132° c. / 48° d.- x = 73°
- y = 56°
- m∠PRO = 56°
Additional Activities
Proof 1.
| Statement | Reason |
|---|---|
| 1. 𝐿₂ ∥ 𝐿₁ | 1. Given |
| 2. ∠2 ≅ ∠1 | 2. Alternate exterior angles are congruent |
| 3. ∠3 ≅ ∠2 | 3. Vertical angles are congruent |
| 4. ∠3 ≅ ∠1 | 4. Transitive property of congruence |
- a. 57° / b. 123° / c. 123° / d. 57° / e. 123° / f. 123° / g. 57° / h. 57°
References
Abuzo, Emmanuel P., Bryant, Merden L., Cabrella, Jem Boy B. Caldez, Belen P., Callanta, Melvin M., Castro, Anastacia Preserfina I., Halabaso, Alicia R., Javier, Sonia P., Nocom, Roger T., and Ternida, Conception S. (2013). Grade 8 Mathematics Learners Module. pp. 441-454. Philippines. Book Media Press, Inc. and Printwell, Inc.
Bernabe, J. & Jose-Dilao, S (2009). Geometry Textbook for Third Year. pp. 73-80. Araneta Avenue, Quezon City, Philippines. SD Publications, Inc.
Boyd, C. (1998). Geometry Integrated, Applications and Connections. pp. 288-320. Columbus, United States of America. Glencoe/McGraw – Hill.
Burger, E., Chard, D., Hall, E., Kennedy P., Leinward S., Renfro, F., Seymour D., & Waits, B. (2007). Holt Geometry pp.142-171. Holt, Rinehart & Winston
Diaz, Zenaida B., Maharlika Mojica P. Manalo, Catalina B., Suzara, Josephine L. Mercado, Jesus P., Esparrago, Marlo S., Reyes, Jr., Nestor V. Next Century Mathematics 8. pp. 547-599. Philippines. Phoenix Publishing House.
Gabriel, Judy L., and Mallari, Ma. Theresa G. (2017). Mathematics for Grade 8: A Spiral Approach. pp. 182 – 188. Cubao, Quezon City, Philippines. Educational Resources Corporation.
Romero, Karl Freidrich Jose D. (2003). Geometry in the Real World. pp. 87-93. Makati City, Philippines. Salesiana Publishers, Inc.
Website Links
- https://www.slideshare.net>mobile. Angles formed by parallel lines cut by transversal – slideshare. Retrieved on December 3, 2019
- https://www.mathisfun.com>parallel lines, pairs of angles – Math is fun. Retrieved on December 3, 2019
Website Links for Videos
- Khan Academy Retrieved form https://youtu.be/3dJ-_t9qvBs. https://youtu.be/RhUOa_w1PiQ. Retrieved on December 3, 2019
For inquiries or feedback, please write or call:
Department of Education – Bureau of Learning Resources (DepEd-BLR) Ground Floor, Bonifacio Bldg., DepEd Complex Meralco Avenue, Pasig City, Philippines 1600
Telefax: (632) 8634-1072; 8634-1054; 8631-4985
Email Address: blr.lrqad@deped.gov.ph * blr.lrpd@deped.gov.ph

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