This is the Grade 7 Mathematics Quarter 2 Module 6 self-learning module on special products. It is a one-lesson Alternative Delivery Mode (ADM) module, First Edition 2020, from DepEd Region XII. It is for Grade 7 learners studying at home or in class. After working through it, learners can use models (algebra tiles) and algebraic methods to multiply binomials and trinomials quickly using patterns.
What learners will learn
After going through this module, learners are expected to use models and algebraic methods to find the:
- product of two binomials
- product of the sum and difference of two terms
- square of a binomial
- cube of a binomial
- product of a binomial and a trinomial
The lesson also includes a short section on the square of a trinomial.
Lessons in this module
The module has one lesson, Lesson 1: Special Products. It starts with a review of multiplying two binomials using the Distributive Property. Next comes an algebra tile activity made from newspaper cut-outs. Then each special product pattern is explained with two worked examples.
Key ideas: the special product patterns
The module gives a general formula for each special product. This table is a quick review.
| Special product | Pattern |
|---|---|
| Product of two binomials | (a + b)(c + d) = ac + ad + bc + bd |
| Sum and difference of two terms | (a + b)(a − b) = a² − b² |
| Square of a binomial | (a + b)² = a² + 2ab + b² and (a − b)² = a² − 2ab + b² |
| Cube of a binomial | (a + b)³ = a³ + 3a²b + 3ab² + b³ and (a − b)³ = a³ − 3a²b + 3ab² − b³ |
| Square of a trinomial | (a + b + c)² = a² + b² + c² + 2ab + 2ac + 2bc |
| Binomial times trinomial | (a + b)(a² − ab + b²) = a³ + b³ and (a − b)(a² + ab + b²) = a³ − b³ |
Product of two binomials and the FOIL method
FOIL stands for First, Outer, Inner, and Last. Multiply the first terms, then the outer terms, then the inner terms, then the last terms, and combine like terms. In the module’s example, (x + 3)(x + 5) gives x² + 5x + 3x + 15, which simplifies to x² + 8x + 15.
With algebra tiles, a large square stands for x², a rectangle for x, and a small square for 1. The area of a rectangle with length x + 2 and width x + 1 is x² + 3x + 2, which equals the product of the two binomials.
Sum and difference of two terms
When two binomials have the same terms but opposite signs, the two middle terms cancel out. Only the difference of the squares is left. For example, (3x + 4)(3x − 4) = 9x² − 16.
Square and cube of a binomial
In the square of a binomial:
- the first term is the square of the first term
- the middle term is twice the product of the two terms
- the last term is the square of the last term
For example, (x − 6)² = x² − 12x + 36.
The cube of a binomial has four terms:
- the cube of a
- three times a²b
- three times ab²
- the cube of b
The module’s example is (x + 5)³ = x³ + 15x² + 75x + 125.
Square of a trinomial
The square of a trinomial has six terms: the squares of the three terms, plus twice each pair of products. For example, (x + 2y + 3z)² = x² + 4y² + 9z² + 4xy + 6xz + 12yz.
Product of a binomial and a trinomial
This pattern works only when the trinomial has the form shown in the table. Then the middle terms cancel and you get a sum or difference of two cubes. For example, (x + 3)(x² − 3x + 9) = x³ + 27 and (x − 4)(x² + 4x + 16) = x³ − 64.
How to use this module
The module is arranged in these parts:
- What I Know: a 15-item multiple-choice pretest that shows what you already know.
- What’s In: a review of multiplying binomials.
- What’s New: an algebra tile activity. Prepare newspaper sheets and scissors, and color the big square black, the rectangle red, and the small square yellow.
- What is It: the discussion and worked examples.
- What’s More: practice with algebra tiles and ten pattern items.
- What I Have Learned: a matching-type exercise.
- What I Can Do: two binomial-times-trinomial items.
- Assessment: a 15-item multiple-choice post-test.
- Additional Activity: find the factor that completes a sum or difference of two cubes.
For learners: Write all answers on a separate sheet of paper, not on the module. Answer keys for every activity and test are at the back. Check your work only after answering, and be honest in using them.
For parents: Help your child prepare the paper tiles for the What’s New activity. Encourage them to finish the pretest before reading the lesson.
For teachers: Use the pretest results to see which learners need extra help. The post-test mirrors the pretest, so you can measure their progress.
Frequently asked questions
What grade and quarter is this Special Products module for?
It is for Grade 7 Mathematics, Quarter 2, Module 6. It is a First Edition 2020 module from DepEd Region XII.
Does the module have an answer key?
Yes. The last pages give answers for the pretest, all activities, the assessment, and the additional activity.
What is the FOIL method?
FOIL stands for First, Outer, Inner, Last. It is a way to multiply two binomials. You multiply each pair of terms in that order, then combine like terms.
What materials are needed for the algebra tile activity?
The module asks for several pages of newspaper and a pair of scissors. You cut and color large squares, rectangles, and small squares.
What is the product of the sum and difference of two terms?
It is the square of the first term minus the square of the second term: (a + b)(a − b) = a² − b². For example, (x + 5)(x − 5) = x² − 25.
Full text of the module
The text below is a transcription of the PDF above, as printed.
Mathematics Quarter 2 – Module 6: Special Products
[illustration: learners reading and studying under a tree, with a teacher at a desk, students around a globe, and a child working by a lamp]
CO_Q2_Mathematics 7_ Module 6
Mathematics – Grade 7 Alternative Delivery Mode Quarter 2 – Module 6: Special Products First Edition, 2020
Republic Act 8293, section 176 states that: No copyright shall subsist in any work of the Government of the Philippines. However, prior approval of the government agency or office wherein the work is created shall be necessary for exploitation of such work for profit. Such agency or office may, among other things, impose as a condition the payment of royalties.
Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them.
Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio
Printed in the Philippines by: _____________________________
Development Team of the Module
Writer: Arnel C. Lapitan Editor: Venus Jane E. Rosete Reviewers: Reynaldo C. Tagala Illustrator: Layout Artist: Maylene F. Grigana, Darven G. Cinchez Management Team: Allan G. Farnazo, CESO IV, Regional Director; Gilbert B. Barrera, Chief, CLMD; Arturo D. Tingson Jr., REPS, LRMS; Peter Van C. Ang-ug, REPS, ADM; Donna S. Panes, CID Chief; Elizabeth G. Torres, EPS – LRMS; Judith B. Alba, Division ADM Coordinator
Department of Education – Region XII Office Address: Regional Center, Brgy. Carpenter Hill, City of Koronadal Telefax: (083) 2288825/ (083) 2281893 E-mail Address: region12@deped.gov.ph
Introductory Message
This Self-Learning Module (SLM) is prepared so that you, our dear learners, can continue your studies and learn while at home. Activities, questions, directions, exercises, and discussions are carefully stated for you to understand each lesson.
Each SLM is composed of different parts. Each part shall guide you step-by-step as you discover and understand the lesson prepared for you.
Pre-tests are provided to measure your prior knowledge on lessons in each SLM. This will tell you if you need to proceed on completing this module or if you need to ask your facilitator or your teacher’s assistance for better understanding of the lesson. At the end of each module, you need to answer the post-test to self-check your learning. Answer keys are provided for each activity and test. We trust that you will be honest in using these.
In addition to the material in the main text, Notes to the Teacher are also provided to our facilitators and parents for strategies and reminders on how they can best help you on your home-based learning.
Please use this module with care. Do not put unnecessary marks on any part of this SLM. Use a separate sheet of paper in answering the exercises and tests. And read the instructions carefully before performing each task.
If you have any questions in using this SLM or any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator.
Thank you.
What I Need to Know
[illustration: a hand pointing a finger inside a circle]
This module was designed and written with you in mind. It is here to help you master Special Products. The scope of this module permits it to be used in many different learning situations. The language used recognizes the diverse vocabulary level of students. The lessons are arranged to follow the standard sequence of the course. But the order in which you read them can be changed to correspond with the textbook you are now using.
The module is comprised of only one lesson:
- Special Products
After going through this module, you are expected to use models and algebraic methods to find the following:
a.) product of two binomials; b.) product of the sum and difference of two terms; c.) square of a binomial; d.) cube of a binomial; and e.) product of a binomial and a trinomial
What I Know
[illustration: a hand holding a pencil inside a circle]
Choose the letter of the best answer. Write the answer on a separate sheet of paper.
What is the product of (x + 5) (x + 3)?
a. x² + 8x + 15
b. x² + 8x – 15
c. x² – 8x + 15
d. x² – 8x – 15Which of the following shows the cube of a binomial?
a. a³ – 4
b. (a – 4)³
c. a³ + 6
d. a + 6³What kind of special product does the model on the right portray?
[illustration: a grid model made of one large red square, blue rectangles, and green small squares arranged in rows]
a. Cube of a binomial
b. Square of a binomial
c. Product of two binomials
d. Product of the sum and difference of two termsWhat is the product of the given expression (x + 4) (x – 4)?
a. x² + 8
b. x² – 8
c. x² + 16
d. x² – 16From the expressions (2x – 2) (x – 1), what are the inner terms?
a. 2x , x
b. 2x , -1
c. -2 , x
d. -2 , -1Which of the following is the same as (x – 6 )²?
a. x² – 12x – 36
b. x² – 12x + 36
c. x² + 12x – 36
d. x² + 12x + 36Which is the same as x³ + y³?
a. (x + y) (x² – xy + y²)
b. (x + y) (x² + xy – y²)
c. (x – y) (x² – xy + y²)
d. (x – y) (x² + xy – y²)What is the product of the given expression (a + 3)²?
a. a² + 6a + 9
b. a² + 6a – 9
c. a² – 6a + 9
d. a² – 6a – 9Which of the following is the product of the given expression (x – 2) (x + 2)?
a. 2x² + 4
b. 2x² – 4
c. x² + 4
d. x² – 4Find the product of the given expression (x + 2) (x² – 2x + 4)?
a. x³ – 8
b. x³ + 8
c. x³ – 4
d. x³ + 4Which of the following is the same as 43²?
a. (40 + 3)²
b. (40 – 3)²
c. (40² + 3)
d. (40 + 3²)Which of the following is equivalent of (34) (26)?
a. (30 + 4) (20 + 6)/2
b. (40 – 6) + (20 + 6)
c. (30 + 4) (30 – 4)
d. (40 – 6) (20 + 6) (40-20)Given the expression (y – 4)², find the product?
a. y² + 8y + 16
b. y² – 8y + 16
c. y² – 8y – 16
d. y² + 8y + 16Which of the following is equivalent to (a + 1)³?
a. a³ + 3a² + 3a + 1
b. a³ + a² + a + 3
c. a³ + 1
d. a³ + 3Find the product of the given expression (2x – 1) (x – 3)?
a. 2x² – 7x + 3
b. 2x² + 7x + 3
c. 2x² – 7x – 3
d. 2x² + 7x – 3
Lesson 1: Special Products
In this lesson you will learn how to use models and algebraic methods to find a.) product of two binomials, b.) product of the sum and difference of two terms, c.) square of a binomial, d.) cube of a binomial, and e.) product of a binomial and a trinomial.
What’s In
[illustration: a hand holding a puzzle piece inside a circle]
Recall that to find the product of two binomials, we use Distributive Property of Multiplication over Addition. Using this property, we multiply every term of one binomial by every term of the other binomial and combine like terms.
Examples for product of binomial
Find the product.
A. (x + 2) (x + 3) C. (3x – 2) (x – 2) B. (2x + 1) (x – 1) D. (3x + 3) (x + 2)
Solution:
A. (x + 2) (x + 3) = (x)(x) + (x)(3) + (2)(x) + (2)(3) = x² + 3x + 2x + 6 = x² + 5x + 6
B. (2x + 1) (x – 1) = (2x)(x) + (2x)(-1) + (1)(x) + (1)(-1) = 2x² – 2x + x – 1 = 2x² – x – 1
C. (3x – 2) (x – 2) = (3x)(x) + (3x)(-2) + (-2)(x) + (-2)(-2) = 3x² – 6x – 2x + 4 = 3x² – 8x + 4
D. (3x + 3) (x + 2) = (3x)(x) + (3x)(2) + (3)(x) + (3)(2) = 3x² + 6x + 3x + 6 = 3x² + 9x + 6
What’s New
[illustration: a hand holding a sprouting plant inside a circle]
At this part, let us use models and algebraic methods in finding a.) product of two binomials, b.) product of the sum and difference of two terms, c.) square of a binomial, d.) cube of a binomial, and e.) product of a binomial and a trinomial.
Activity 1.
This activity uses algebra tiles to find the general formula for the product of two binomials. To do the activity, prepare several pages of newspapers and a pair of scissors. Cut at least three sheets of paper using the following pattern. Color the big square sheet in black, the rectangle sheet in red and the small square in yellow.
[illustration: three outlined shapes: a large square, a tall rectangle, and a small square]
Task A: Write your answer to the following questions on a separate sheet of paper.
- If the smallest figure is a square measuring 1 unit in each side, form a square that measures 2 units on each side. What is the area of this square?
- Determine how many squares of 1 unit in each side will be used to cover the figure colored in black and in red.
Cut additional sheets of paper and follow the pattern below to create a rectangle. Then answer the following questions below.
[chart: grid diagram; figure formed by placing together the large squares, rectangles, and small squares]
The figure on the left is formed by placing together the 6 large squares, 16 rectangles and 25 small squares. Let the small square measures 1 unit in each side, then the dimensions would be as follow:
[illustration: small square] = 1 unit by 1 unit
[illustration: rectangle] = 1 unit by 2 units
[illustration: large square] = 2 units by 2 units
Suppose each large squares has a dimension of x units, the rectangle is x units by 1 unit and the small squares has a side length of 1 unit.
Recall that the area of a square and a rectangle is determined by multiplying their lengths and their widths. Then determine the area of the large square, the rectangle and the small square.
Task B: Write your answer to the following questions in a separate sheet of paper.
- What is the area of a rectangle when the rectangle has a length of x+2 and a width of x +1 using algebra tiles?
- What is the area of the illustration represented by the algebra tiles above?
What is the product of x + 1 and x + 2? Is it the same as the area of the rectangle in Task B, Question No. 1?
Note that the area of a rectangle is the product of its length and its width and if the dimensions are represented by binomials, then the area of the rectangle is equivalent to the product of the two binomials which is x² + 3x + 2.
Task C: Write your answer to the following questions in a separate sheet of paper.
- Use algebraic method to find the product of the following.
a. (x + 2) (x + 3)
b. (2x – 1) (x + 4)
c. (2x + 1) (2x + 3) - How will you represent x – 1 using algebra tiles?
What is It
Use Models and Algebraic Methods to find the special product:
a). Product of Two Binomials
The product of (a + b) (c + d) is ac + ad + bc + bd. This is the general formula for the product of two binomials (a + b) (c + d).
The general form may be obtained using the FOIL method. The letters FOIL stands for First, Outer, Inner and Last. First means multiply the terms which occur first in each binomial. The Outer means multiply the outer terms in each binomial. Inner means multiply the inner terms of the two binomials. And Last implies that we multiply the last terms of the two binomials. Then simplify the results by combining like terms.
Example 1. Find the product of (x + 3) (x + 5).
Solution:
[illustration: FOIL diagram with arrows labeled O, F, I, L over (x + 3) (x + 5); a brace beside the First, Outer, Inner and Last products is labeled “add”]
First: (x) (x) = x² Outer: (x) (5) = 5x Inner: (3) (x) = 3x Last: (3) (5) = 15
(x + 3) (x + 5) = x² + 5x + 3x + 15 = x² + 8x + 15
Example 2. Find the product of (x – 4) (3x + 2)
Solution:
(x – 4) (3x + 2) First: (x) (3x) = 3x² Outer: (x) (2) = 2x Inner: (-4) (3x) = -12x Last: (-4) (2) = -8
(x + 4) (3x + 2) = 3x² + 2x – 12x – 8 = 3x² – 10x – 8
[transcriber’s note: the printed result line of Example 2 reads “(x + 4) (3x + 2)”, not “(x – 4) (3x + 2)”]
b). Product of the Sum and Difference of Two Terms
The product of the sum and difference of two terms is given where the first and second terms of the two binomials are the same, hence the only different is the operation sign, given by the general formula:
(a + b) (a – b) = a² – b²
The general formula (a + b) (a – b) = a² – b² is derived using the FOIL method.
(a + b) (a – b) = a² + ab – ab – b²
Since the two middle terms are opposites, their sum is 0. Thus, the pattern of the product of the sum and difference of two terms is a² – b².
Example 1. Find the product of (x + 5) (x – 5).
Solution:
Let a = x and b = 5 Using the special product of the form a² – b², we have: (x + 5) (x – 5) = (x)² – (5)² = x² – 25
Example 2. Find the product of (3x + 4) (3x – 4).
Solution:
Let a = 3x and b = 4 Using the special product of the form a² – b², we have: (3x + 4) (3x – 4) = (3x)² – (4)² = 9x² – 16
c.) Square of a Binomial
The square of a binomial (a + b)² is the product of a binomial when multiplied to itself. FOIL method can be used in finding the general formula of the square of a binomial.
(a + b)² = (a + b) (a + b) = a² + ab + ab + b² = a² + 2ab + b²
(a – b)² = (a – b) (a – b) = a² – ab – ab + b² = a² – 2ab + b²
- The first term of the product is always the square of the first term in the binomial.
- The second term of the product is always twice the product of the two terms in the binomial.
- The last term of the product is always the square of the last term in the binomial.
Example 1. Find the product of (x + 4)².
Solution:
Using the special product of the square of the binomial, we have: (a + b)² = a² + 2ab + b² Let a = x and b = 4. Substituting these values, we get: (x + 4)² = x² + 2(x)(4) + 4² = x² + 2(4x) + 4² = x² + 8x + 16
Example 2. Find the square of (x – 6)².
Solution:
Using the special product of the square of the binomial, we have: (a – b)² = a² – 2ab + b² Let a = x and b = 6. Substituting these values, we get: (x – 6)² = x² – 2(x)(6) + (6)² = x² – 2(6x) + (6)² = x² – 12x + 36
d.) Cube of a Binomial
The cube of a binomial can be expressed as (a + b)²(a + b) because of the Law of Exponents. By actually multiplying, we get:
(a + b)³ = (a + b)²(a + b) Square the binomial. = (a² + 2ab + b²)(a + b) Distributive Property = a³ + 2a²b + ab² + a²b +2ab² + b³ Combine similar terms (a + b)³ = a³ + 3a²b + 3ab² + b³
The cube of a binomial (a + b) is the sum of four terms where each term can be obtained as follows:
- First Term: The cube of a
- Second Term: Three times the product of a² and b
- Third Term: Three times the product of a and b²
- Fourth Term: The cube of b
For all numbers a and b, the cube of a binomial patterns are:
(a + b)³ = a³ + 3a²b + 3ab² + b³ (a – b)³ = a³ – 3a²b + 3ab² – b³
Example 1. Find the product of (x + 5)³.
Solution:
Using the special product of the cube of the binomial, we have: (a + b)³ = a³ + 3a²b + 3ab² + b³ Let a = x and b = 5. Substituting these values, we get: (x + 5)³ = x³ + 3(x)²(5) + 3(x)(5)² + (5)³ = x³ + 3(5x²) + 3(x)(25) + 125 = x³ + 15x² + 75x + 125
Example 2. Find the product of (x – 6)³.
Solution:
Using the special product of the cube of the binomial, we have: (a – b)³ = a³ – 3a²b + 3ab² – b³ Let a = x and b = 6. Substituting these values, we get: (x – 6)³ = x³ – 3(x)²(6) + 3(x)(6)² – (6)³ = x³ – 3(6x²) + 3(x)(36) – 216 = x³ – 18x² + 108x – 216
e.) Square of Trinomials
The square of a trinomial (a + b + c) has six terms.
(a + b + c)² = a² + b² + c² + 2ab + 2ac + 2bc
First term: Square of the first term a² Second term: Square of the second term b² Third term: Square of the third term c² Fourth term: Twice the product of the first term and the second term 2ab Fifth term: Twice the product of the first term and the third term 2ac Sixth term: Twice the product of the second term and the third term 2bc
Example 1: Find the product of (x + 2y + 3z)².
Solution:
First term: (x)² = x² Second term: (2y)² = 4y² Third term: (3z)² = 9z² Fourth term: 2(x)(2y) = 4xy Fifth term: 2(x)(3z) = 6xz Sixth term: 2(2y)(3z) = 12yz
Thus, (x + 2y + 3z)² = x² + 4y² + 9z² + 4xy + 6xz + 12yz.
Example 2. Find the product of (2x – 3y + 4z)².
Solution:
First term: (2x)² = 4x² Second term: (-3y)² = 9y² Third term: (4z)² = 16z² Fourth term: 2(2x)(-3y) = -12xy Fifth term: 2(2x)(4z) = 16xz Sixth term: 2(-3y)(4z) = -24yz
Thus, (2x – 3y + 4z)² = 4x² + 9y² + 16z² – 12xy + 16xz – 24yz.
f.) Product of a Binomial and a Trinomial
The product of a binomial and a trinomial can be expressed as the sum or difference of two cubes if they are in the following form:
(a + b)(a² – ab + b²) or (a – b)(a² + ab + b²)
If the given is not of the above forms, the pattern is not applicable.
(a+b) (a² – ab + b²) = a(a² – ab + b²) + b( a² – ab + b²) Apply Distribute Property = a³ – a²b +ab² + a²b – ab² + b³ Cancel out opposite terms = a³ + b³
[transcriber’s note: in the original, the terms –a²b, +ab², +a²b and –ab² are struck through with cancellation lines]
(a – b) (a² + ab + b²) = a(a² + ab + b²) – b( a² + ab + b²) Apply Distribute Property = a³ + a²b + ab² – a²b – ab² – b³ Cancel out opposite terms = a³ – b³
[transcriber’s note: in the original, the terms +a²b, +ab², –a²b and –ab² are struck through with cancellation lines]
Thus, the general forms can now be stated as:
(a + b) (a² – ab + b²) = a³ + b³ (a – b) (a² + ab + b²) = a³ – b³
Example 1. Find the product of (x + 3)(x² – 3x + 9).
Solution:
Using the special product of a binomial and a trinomial, we have: (a + b) (a² – ab + b²) = a³ + b³
Let a = x and b = 3. Substituting these values, we get: (x + 3) (x² – 3x + 9) = (x)³ + (3)³ = x³ + 27
Example 2. Find the product of (x – 4) (x² + 4x +16)
Solution:
Using the special product of a binomial and a trinomial, we have: (a – b) (a² + ab + b²) = a³ – b³
Let a = x and b = 4. Substituting these values, we get: (x – 4) (x² + 4x +16) = (x)³ – (4)³ = x³ – 64
What’s More
Do the following activities as directed.
Activity 1. Use the algebra tiles to find the product of the following:
- (x + 1) (x + 2)
- (2x + 1) (2x + 3)
Activity 2. Use the patterns on finding the product of the following. Show your solutions.
- (a + 2) (a – 5)
- (b + 4) (b + 3)
- (c + 3) (c – 3)
- (d – 5) (d + 5)
- (m + 6)²
- (n – 8)²
- (p – 1)³
- (x + 5)³
- (x + 2) (x² – 2x + 4)
- (3x + 2y + z)²
What I Have Learned
Find the product of the expressions found in column A. Match the correct answer in column B. Write only the letter of your answer in the space provided.
| Column A | Column B |
|---|---|
| _____ 1. (x + 5) (x + 1) | a. x² -100 |
| _____ 2. (3x + 5) (3x – 5) | b. x² + 4x + 4 |
| _____ 3. (x + 2) (x + 2) | c. x³ + 6x² + 12x + 8 |
| _____ 4. (x + 2) (x + 2) (x + 2) | d. 9x² – 25 |
| _____ 5. (x + 10) (x – 10) | e. x² + 6x + 5 |
| _____ | f. x² – 6x + 5 |
What I Can Do
Use models and algebraic methods to find product of a binomial and a trinomial as follows:
- (y + 2) (y² – 2y + 4)
- (3x + 2 ) (9x² – 6x + 4)
Assessment
Multiple Choice. Choose the letter of the correct answer. Write you answer on a separate sheet of paper.
What is the product of (2x – 3) (3x + 4)?
- A. 6x² – x – 12
- B. 6x² – x + 12
- C. 6x² – 17x – 12
- D. 6x² – 17x + 12
Which of the following shows the cube of a binomial?
- A. p + 27
- B. p³ + 27
- C. p³ – 27
- D. (p + 27)³
What is the third term in the product of (x + 2y + 3z)²?
- A. 3z
- B. 3z²
- C. 9z
- D. 9z²
What is the product of the given expression (x + 7) (x – 7)?
- A. (x² + 14)
- B. (x² – 14)
- C. (x² + 49)
- D. (x² – 49)
From the expressions (5x – 2) (x – 3), what are the inner terms?
- A. 2x , x
- B. 2x , -1
- C. -2 , x
- D. -2 , -1
Which of the following is the same as (x – 9)²?
- A. x² – 18x – 81
- B. x² – 18x + 81
- C. x² + 18x – 81
- D. x² + 18x + 81
Which of the following is the same as a³ + b³?
- A. (a + b) (a² – ab + b²)
- B. (a + b) (a² + ab – b²)
- C. (a – b) (a² – ab + b²)
- D. (x – b) (a² + ab – b²)
What is the product of the given expression (y + 5)²?
- A. y² + 10y + 25
- B. y² + 10y – 25
- C. y² – 10y + 25
- D. y² – 10a + 25
Which of the following is the product of the given expression (x – 10) (x + 10)?
- A. 2x² + 100
- B. 2x² – 100
- C. x² + 100
- D. x² – 100
Find the product of the given expression (x – 10) (x² + 10x + 100)?
- A. x³ – 1000
- B. x³ + 1000
- C. x³ – 100
- D. x³ + 100
What is the product of the given expression (a + 2)³?
- A. a³ + 6a² + 6a + 2
- B. a³ + 6a² + 6a + 6
- C. a³ + 6a² + 12a + 6
- D. a³ + 6a² + 12a + 8
What is the product of the expression (x + 5) (x – 5)?
- A. x² + 10x -25
- B. x² + 10x +25
- C. x² – 25
- D. x² + 25
Given the expression (b – 1)², find the product?
- A. b² + 2b + 1
- B. b² – 2b + 1
- C. b² – 2b – 1
- D. b² + 2b – 1
What is the product of the expression (t + 7)²?
- A. t² – 14t – 49
- B. t² + 14t – 49
- C. t² – 14t + 49
- D. t² + 14t + 49
Find the product of the given expression (2d – 1) (d – 3)?
- A. 2d² – 7d + 3
- B. 2d² + 7d + 3
- C. 2d² – 7d – 3
- D. 2d² + 7d + 3
Additional Activity
What should be multiplied to the given terms to get the sum or difference of two cubes? Then, give the product.
- (x – 7)
- (x + 8)
- (4x + 1)
- (5x – 3)
- (x² + 2x + 4)
Answer Key
[transcriber’s note: this page is printed upside down; the sections are transcribed upright, in the order they appear on the page]
[illustration: answer key key-and-hand emblem]
What I Know
- A
- B
- B
- D
- C
- B
- A
- A
- D
- B
- A
- C
- B
- A
- A
What’s New
Task A
- 2 units x 2 units = 4 unit²
- 3 units x 2 units = 6 unit²
Task B
- The area of the rectangle is x² + 3x + 2.
- The area is the sum of all the algebra tiles. A = 6x² + 18x + 45
[illustration: algebra tile rectangle labeled x², x, 1]
Task C
- a. x² + 5x + 6
b. 2x² + 7x – 4
c. 4x² + 8x + 3 - Color the tile -1 black to denote subtraction.
[illustration: algebra tile arrangement with a black -1 tile]
What’s More
Activity 1
- x² + 3x + 2
- 4x² + 8x + 3
[illustration: algebra tile arrangements for Activity 1]
Activity 2
- a² – 3a – 10
- b² + 7b + 12
- c² – 9
- d² – 25
- m² + 12m + 36
- n² – 16n + 64
- p³ – 3p² + 3p – 1
- x³ + 15x² + 75x + 125
- x³ + 8
- 9x² + 4y² + z² + 12xy + 6xz + 4yz
[illustration: algebra tile arrangement for Activity 2]
What I Have Learned
- E
- D
- B
- C
- A
What Can I Do
- y³ + 8
- 27x³ + 8
Assessment
- A
- D
- D
- D
- C
- B
- A
- A
- D
- A
- D
- C
- B
- D
- A
Additional Activity
- x² + 7x + 49 ; x³ – 343
- x² – 8x + 64 ; x³ + 512
- 16x² – 4x + 1 ; 64x³ + 1
- 25x² + 15x + 9 ; 125x³ – 27
- x – 2 ; x³ – 8
References
- Department of Education-National Program Support for Basic Education Elementary Algebra for First Year.
- Department of Education-Instructional Materials Council Secretariat ( DepEd – IMCS), Mathematics – Grade 7 Teachers Guide First Edition, 2013 ISBN: 978-971-9990-61-1
- Charles P Mckeague, et.al. (2013). Basic College Mathematics Anvil Publishing, Inc. Mandaluyong City 1550 Philippines
For inquiries or feedback, please write or call:
Department of Education – Bureau of Learning Resources (DepEd-BLR)
Ground Floor, Bonifacio Bldg., DepEd Complex Meralco Avenue, Pasig City, Philippines 1600
Telefax: (632) 8634-1072; 8634-1054; 8631-4985
Email Address: blr.lrqad@deped.gov.ph * blr.lrpd@deped.gov.ph
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