General Mathematics Quarter 1 Module 13: Representations of Inverse Functions

General Mathematics Q1 Module 13 shows how to represent the inverse of a one-to-one function using tables of values and graphs, with an answer key.

This is the Self-Learning Module (SLM) for General Mathematics, Quarter 1, Module 13: “Representations of Inverse Functions,” for Senior High School learners. It has one lesson that shows how to represent the inverse of a one-to-one function with a table of values and a graph. After this module, learners should be able to build both representations and explain how a function and its inverse are related.

On this page 8 sections

What learners will learn

After going through this module, learners are expected to:

  • represent an inverse function through its (a) table of values and (b) graph.

Lessons in this module

  • Lesson 1: Representing an Inverse Function through Table of Values, and Graph. The lesson explains that only a one-to-one function has an inverse that is also a function. It then shows how to make a table of values for a function and its inverse, and how to graph both on the same plane.

Key ideas: what an inverse function is

The module defines the inverse this way: if a function f has domain A and range B, its inverse has domain B and range A. The inverse of f is written f-1, and f-1(y) = x if and only if f(x) = y.

Other points the lesson stresses:

  • Only one-to-one functions have inverses that are functions. If a function is many-to-one, its inverse is one-to-many, which is not a function.
  • Horizontal line test. Use it on a graph to check whether a function is one-to-one. If the graph passes, the function is one-to-one.
  • Swapping values. The x-values of the function become the y-values of the inverse, and the y-values of the function become the x-values of the inverse.
  • Symmetry about y = x. The graph of the inverse is the graph of the function reflected about the line y = x, so the two graphs are symmetric about that line.

Worked example: f(x) = 2x + 3 and its inverse

The module uses f(x) = 2x + 3, whose inverse is f-1(x) = (x – 3)/2.

Step 1: Make a table for f(x). Substitute x = -2, -1, 0, 1, 2. For example, f(-2) = 2(-2) + 3 = -1.

x-2-1012
f(x)-11357

Step 2: Use the outputs as inputs for the inverse. Substitute -1, 1, 3, 5, 7 into f-1(x) = (x – 3)/2. For example, f-1(-1) = (-1 – 3)/2 = -2.

x-11357
f-1(x)-2-1012

Step 3: Graph both lines. Plot each table as a line on the same coordinate plane. A broken diagonal line, y = x, passes through the origin and the point where the two lines meet. The two graphs are mirror images across it.

The module also gives a shortcut: graph the function first, then switch the x and y values of each point to get the graph of the inverse.

Activities in the module

  • What’s New, “You Complete Me!”: match functions with their inverses and possible values, such as f(0) or f-1(1), to review how to find an inverse.
  • Activity 13.1: make tables of values from x = -2 to 2 for five functions, such as f(x) = x + 2 and g(x) = (3x + 5)/8.
  • Activity 13.2: graph six one-to-one functions and their inverses, such as f(x) = 3x – 4 and f(x) = (x + 3)/2.
  • What I Have Learned: three reflection questions about the graphs and the use of tables of values.
  • What I Can Do: a real-life task on Celsius and Fahrenheit. Learners find the linear function from the freezing and boiling points of water, find its inverse, and look for the temperature that is the same on both scales.
  • Additional Activities: find the inverse of f(x) = (x + 7)/3 and f(x) = (x – 2)/5, and make a table of values for each.

How to use this module

  1. Answer the 15-item pretest (What I Know) first. It shows what you already know and whether you need help from your teacher.
  2. Work through the parts in order: What’s In, What’s New, What is It, What’s More, What I Have Learned, and What I Can Do.
  3. Take the 15-item Assessment at the end to check your learning, then do the Additional Activities.
  4. Write all answers on a separate sheet of paper and do not mark the module.

For learners: answer keys for the tests and activities are at the back, including a full solution to the temperature task. Check your work honestly after you answer.

For parents and facilitators: help your child follow the order of the parts, and contact the teacher if a task is too hard.

For teachers: the Notes to the Teacher ask you to make sure learners do each task. Provide solutions for exercises they cannot answer, especially the Additional Activities.

Frequently asked questions

What grade and quarter is this module for?

It is a Senior High School General Mathematics module for Quarter 1. It is Module 13 in the series.

What does the module teach?

It teaches how to represent the inverse of a one-to-one function with a table of values and a graph. It also covers the horizontal line test and the symmetry of the two graphs about the line y = x.

How do you graph the inverse of a function?

Graph the function first. Then switch the x and y values of each point to plot the inverse. The two graphs will be mirror images across the line y = x.

Does the module have an answer key?

Yes. The answer key covers the pretest, the activities, the assessment, the Additional Activities, and the temperature conversion task.

Why must a function be one-to-one to have an inverse function?

A many-to-one function has an inverse that is one-to-many, and a one-to-many relation is not a function. Only a one-to-one function has an inverse that is also a function.

Full text of the module

The text below is a transcription of the PDF above, as printed.

Senior High School

General Mathematics Quarter 1 – Module 13: Representations of an Inverse Functions

[illustration: teachers and learners studying outdoors and indoors, with a globe and a lamp]

CO_Q1_General Mathematics SHS Module 13

General Mathematics Alternative Delivery Mode Quarter 1 – Module 13: Representations of an Inverse Functions First Edition, 2020

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Borrowed materials (i.e., songs, stories, poems, pictures, photos, brand names, trademarks, etc.) included in this module are owned by their respective copyright holders. Every effort has been exerted to locate and seek permission to use these materials from their respective copyright owners. The publisher and authors do not represent nor claim ownership over them.

Published by the Department of Education Secretary: Leonor Magtolis Briones Undersecretary: Diosdado M. San Antonio

Development Team of the Module

Writer: Angelo S. Villanueva

Editors: Elizabeth B. Dizon, Anicia J. Villaruel, and Roy O. Natividad

Reviewers: Fritz A. Caturay, Necitas F. Constante, Dexter M. Valle, and Jerome A. Chavez, Raiza Ann E. Lipardo, Mary Ann C. Guiang and Moahna Aura M. Mancenido

Illustrator: Dianne C. Jupiter and Michael A. Alonzo

Layout Artist: Noel Rey T. Estuita

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Printed in the Philippines by _____

Department of Education – Region IV-A CALABARZON

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General Mathematics Quarter 1 – Module 13: Representations of Inverse Functions

Senior High School

Introductory Message

This Self-Learning Module (SLM) is prepared so that you, our dear learners, can continue your studies and learn while at home. Activities, questions, directions, exercises, and discussions are carefully stated for you to understand each lesson.

Each SLM is composed of different parts. Each part shall guide you step-by-step as you discover and understand the lesson prepared for you.

Pre-tests are provided to measure your prior knowledge on lessons in each SLM. This will tell you if you need to proceed on completing this module or if you need to ask your facilitator or your teacher’s assistance for better understanding of the lesson. At the end of each module, you need to answer the post-test to self-check your learning. Answer keys are provided for each activity and test. We trust that you will be honest in using these.

In addition to the material in the main text, Notes to the Teacher are also provided to our facilitators and parents for strategies and reminders on how they can best help you on your home-based learning.

Please use this module with care. Do not put unnecessary marks on any part of this SLM. Use a separate sheet of paper in answering the exercises and tests. And read the instructions carefully before performing each task.

If you have any questions in using this SLM or any difficulty in answering the tasks in this module, do not hesitate to consult your teacher or facilitator.

Thank you.

What I Need to Know

This module was designed and written with you in mind. It is here to help you understand the inverse function. Particularly, this will provide you guide on how to find the inverse of a one-to-one function. Enjoy as you immerse yourself in solving for the inverse function intuitively or using a set of more established steps.

The module is composed of one lesson, namely:

  • Lesson 1 – Representing an Inverse Function through Table of Values, and Graph

After going through this module, you are expected to:

  1. represent an inverse function through its: (a) table of values and (b) graph.

What I Know

Read the given questions carefully and choose the correct options. Write the letter of your choice on a separate sheet of paper.

  1. Which of the following graphs do not belong to the group?

a. [chart: graph; choice a; plots y = x³ passing through the origin, with axes x and y]

b. [chart: graph; choice b; three straight lines and one dotted line crossing near the same point; no labels]

c. [chart: graph; choice c; two straight lines on a coordinate grid; no labels]

d. [chart: graph; choice d; labels f(x), y = x, and f⁻¹(x) on three lines; no values labeled]

  1. The graph of a one-to-one function and its inverse function is ______________


    a. Hyperbolic
    b. Parabola
    c. Parallel
    d. Symmetric


  2. Which of the following terms deals with inverse?


    a. alternate
    b. delete
    c. eliminate
    d. interchange


  3. Which of the following equations is used to test if the graph of a one-to-one function and its inverse function?


    a. f(x) = y
    b. y = x
    c. f(x) = x
    d. f(x) = x+y


  4. Which of the following ordered pairs of an inverse function has its one-to-one function indicated in the table below?


f(x)34567
y-2-1012

a. f⁻¹(x) = {(-3,-2), (-4,-1), (0,5), (-1,6), (-2, 7)} b. f⁻¹(x) = {(3,2), (4,1), (0,-5), (1,-6), (2,-7)} c. f⁻¹(x) = {(3,-2), (4,-1), (0,5), (1,6), (2, 7)} d. f⁻¹(x) = {(-2,3), (-1,4), (0,5), (1,6), (2,7)}

  1. What test is used to determine if a function is one-to-one function?


    a. Diagonal line test
    b. Horizontal line test
    c. Straight line test
    d. Vertical line test


  2. What is the missing value in the table below with the equation, f(x) = x -3?


f(x)357911
y02_____68

a. 3 b. 4 c. 5 d. 6

  1. The illustration shows the one-to-one function and its inverse, which pair has the correct functions?

[chart: graph; one-to-one function and its inverse; two straight lines on a coordinate grid with x-axis labeled from -12 to 12 and y-axis labeled; no values labeled]

a. f(x) = 2x − 3 and f⁻¹(x) = (x + 3)/2 b. f(x) = 3x − 2 and f⁻¹(x) = (x + 2)/3 c. f(x) = x − 3 and f⁻¹(x) = (x + 1)/3 d. f(x) = 2x + 3 and f⁻¹(x) = (x − 3)/2

  1. Which term was used to represent the x-values of the function are the y-values of its inverse, and the y-values of the function are the x-values of its inverse?


    a. Coordinating values
    b. Intersecting values
    c. Table of values
    d. True values


  2. Which is true about f(x) = 2x – 1 and y = (x + 1)/2?


    a. They are inverse functions.
    b. They are not one-to-one functions.
    c. The graphs are parallel to each other.
    d. The graphs intersect at two or more points.


  3. Which of the following graphs best described f(x) = 2x – 1 and y = (x + 1)/2 ?


  • a. [chart: graph a; two straight lines on a coordinate grid; values are not labeled on the chart]
  • c. [chart: graph c; two straight lines on a coordinate grid; values are not labeled on the chart]
  • b. [chart: graph b; two straight lines on a coordinate grid; values are not labeled on the chart]
  • d. [chart: graph d; two straight lines on a coordinate grid; values are not labeled on the chart]
  1. If the function is one-to-one and has x and y-values of (2, -6), what is its inverse values?
  • a. (-2, 6)
  • b. (6,-2)
  • c. (-6,2)
  • d. (6, 2)
  1. Which term best complete the sentence: To graph the inverse all you need to do in the coordinates of each ordered pair is to _________________________.
  • a. delete
  • b. investigate
  • c. switch
  • d. replace
  1. All of the following are used in the representation of inverse function, EXCEPT.
  • a. f-1(x)
  • b. graph
  • c. range
  • d. table of values
  1. Which of the following table of values represent the correct inverse function of f(x) = 2x + 3?

a.

f-1(x)-2-1012
y-11357

b.

f-1(x)-11357
y-2-1012

c.

f-1(x)1-1-3-5-7
y-2-1012

d.

f-1(x)-11357
y210-1-2

Lesson 1 – Representing an inverse function through table of values, and graph

Among the functions, only a one-to-one function has an inverse which is a function also which can be represented in table of values and graphs.

What’s In

You have learned different types of functions in the previous lessons. Do you ever wonder if inverses of functions are functions as well? That is, both the original equation and its inverse are both functions. In this lesson, you will delve into these functions with function inverses.

Notes to the Teacher

Enable learners to perform each task or activity in this module. Solutions should be provided for exercises which will not be successfully answered by the learners especially for “Additional Activities” Part.

What’s New

You Complete Me!

Below is a table with function f(x) and its inverse f-1(x); and possible values. To enjoy this activity, you need to review the concept of finding the inverse of a one-to-one function and investigate on the possible values of the function and its inverse by completing the statements below the table as many as you can.

FunctionsFunctionsFunctionsPossible ValuesPossible ValuesPossible Values
f(x) = 2x + 3f-1(x) = (x + 3)/5f(x) = 3x – 1f(0) = -3f-1(-1) = -2f-1(1) = 2/3
f(x) = 3x – 2f-1(x) = (x – 1)/3f-1(x) = (x – 3)/2f(1) = 5f(-1) = -4f(5) = 13
f(x) = 5x – 3f-1(x) = (x + 2)/3f-1(x) = (x + 1)/3f-1(1) = 1f-1(0) = -3/2f-1(0) = 3/5
  1. The function _____ has an inverse function of _____ with possible values of the function as _____ and _____.


  2. The function _____ has an inverse function of _____ with possible values of the function as _____ and _____.


  3. The function _____ has an inverse function of _____ with possible values of the function as _____ and _____.


  4. The function _____ has an inverse function of _____ with possible values of the function as _____ and _____.


What is It
Inverse Function Defined with table of values and graph

The inverse of a function is a function with domain B and range A given that the original function has domain A and range B.

This inverse function of function f is denoted by f-1. It is defined by the equation f-1(y) = x if and only if f(x) = y for any y in range B. Since both are functions, then a function has to be one-to-one for its inverse to be a function at the same time. If it is a many-to-one function, its inverse is one-to-many which is not a function.

In using table of values of the functions, first we need to ascertain that the given function is a one-to-one function wherein no x-values are repeated. It is represented as the x-values of the function resulted as the y-values of its inverse, and the y-values of the function are the x-values of its inverse. Also, the graph should correspond to a one to one function by applying the Horizontal Line test. If it passes the test, the corresponding function is one-to-one. Given the graph of a one-to-one function, the graph of its inverse can be obtained by reflecting the graph about the line y = x.

Example 1

In the given function f(x) = 2x + 3, with an inverse function of f-1(x) = (x – 3)/2 as discussed in the previous activity. Let us use the x-values to complete the table of values in y-values for the f(x) = 2x + 3.

f(x)-2-1012
y

In order to complete the y-values, let us substitute each x-value from the function, f(x) = 2x + 3.

If x = -2, f(-2) = 2(-2) + 3, by solving it, f(-2) = -4 + 3, then, f(-2) = -1.

If x = -1, f(-1) = 2(-1) + 3, by solving it, f(-1) = -2 + 3, then, f(-1) = 1.

If x = 0, f(0) = 2(0) + 3, by solving it, f(0) = 0 + 3, then, f(0) = 3.

If x = 1, f(1) = 2(1) + 3, by solving it, f(1) = 2 + 3, then, f(1) = 5.

If x = 2, f(2) = 2(2) + 3, by solving it, f(2) = 4 + 3, then, f(2) = 7.

Thus, the table of values for f(x) = 2x + 3 is presented below with its corresponding graph.

f(x)-2-1012
y-11357

[chart: line graph of f(x) = 2x + 3 on a coordinate grid; axis tick labels printed; values are not labeled on the chart]

At this point, let us investigate on the inverse function f-1(x) = (x – 3)/2 by using the y-values from the original function as x-values of the inverse function. Observe the same process in completing the table of values by substituting the x-values to the given inverse function. Now the table of values will be as follows:

f-1(x)-11357
y

In order to complete the y-values, let us substitute each x-value from the given inverse function, f-1(x) = (x – 3)/2.

If f-1(-1), f-1(-1) = ((-1) – 3)/2, by solving it, f-1(-1) = -4/2, then f-1(-1) = -2.

If f-1(1), f-1(1) = ((1) – 3)/2, by solving it, f-1(1) = -2/2, then f-1(1) = -1.

If f-1(3), f-1(3) = ((3) – 3)/2, by solving it, f-1(3) = 0/2, then f-1(3) = 0.

If f-1(5), f-1(5) = ((5) – 3)/2, by solving it, f-1(5) = 2/2, then f-1(5) = 1.

If f-1(7), f-1(7) = ((7) – 3)/2, by solving it, f-1(7) = 4/2, then f-1(7) = 2.

Thus, the table of values for f-1(x) = (x – 3)/2 is presented below.

f-1(x)-11357
y-2-1012

[chart: line graph of the inverse function f-1(x) = (x – 3)/2 on a coordinate grid; axis tick labels printed; values are not labeled on the chart]

This is the graph of the inverse function, f-1(x) = (x – 3)/2. In the next page, the graphs of the two functions will be presented to you. Let us see how it looks like!

[chart: graph of f(x) = 2x + 3, f-1(x) = (x – 3)/2, and a broken diagonal line on one coordinate grid; axis tick labels printed; values are not labeled on the chart]

As you observed, there is an diagonal line (represented as broken line) across the origin to the point of intersection of the line f(x) = 2x + 3 and f-1(x) = (x – 3)/2.

However, for easy steps, if you’re asked to graph a function and its inverse, all you must do is graph the function and then switch all x and y values in each point to graph the inverse. Just look at all those values switching places from the f(x) function to its inverse f-1(x) (and back again). Furthermore, the two graphs will be symmetric about the line y = x.

What’s More
Activity 13.1

Intuitively, give the table of values of each of the following functions. (Use the values from -2 to 2).

  1. f(x) = x + 2
  2. g(x) = 12x − 1
  3. h(x) = −x/4
  4. f(x) = x
  5. g(x) = (3x+5)/8
Activity 13.2

Illustrate the graph of the given one-to-one function and its inverse.

  1. f(x) = 3x − 4
  2. f(x) = 5x + 3
  3. f(x) = 7x − 5
  4. f(x) = (x − 2)/3
  5. f(x) = (x + 3)/2
  6. f(x) = (x + 5)/4
What I Have Learned

Now, answer the following questions.

  1. Describe the graph of a one-to-one function and its inverse?
  2. What will you do to graph the inverse function?
  3. How important it is to present table of values of a function?
What I Can Do

In real life, temperature conversions provide a rich source of linear functions which are encountered not only in science but also in our everyday lives when we travel abroad. This time try to explore the task below, the first part of this task provides an opportunity to construct a linear function given two input-output pairs. The second part investigates the inverse of a linear function while the third part requires reasoning about quantities and/or solving a linear equation.

Let f be the function that assigns to a temperature in degrees Celsius its equivalent in degrees Fahrenheit.

A. The freezing point of water in degrees Celsius is 0 while in degrees Fahrenheit it is 32. The boiling point of water is 100 degrees Celsius and 212 degrees Fahrenheit. Given that the function f is linear, use this information to find an equation for f.

B. Find the inverse of the function f and explain its meaning in terms of temperature conversions.

C. Is there a temperature which is the same in degrees Celsius and in degrees Fahrenheit? Explain how you know.

Assessment

Multiple Choice. Choose the letter of the best answer. Write the letter of your choice on a separate sheet of paper.

  1. Which of the following graphs do not belong to the group?

a. [illustration: two solid lines and one dashed line crossing near the origin on a plain axis grid] b. [illustration: three straight lines, one dotted, crossing near (-2, -2) on a grid] c. [illustration: a gray straight line and a parabola opening upward, with the shaded background] d. [illustration: two parallel straight lines on a coordinate grid]

  1. The following are the behaviors of a graph of a one-to-one function and its inverse function, EXCEPT.
    a. intersecting
    b. Parabola
    c. Parallel
    d. Symmetric


  2. Which of the following terms do not deals with inverse?
    a. alternate
    b. interchange
    c. switch
    d. reverse


  3. Which of the following equations is used to test if the graph of a one-to-one function and its inverse function?
    a. f(x) = y
    b. f(x) = x
    c. f(x) = x+y
    d. y = x


  4. Which of the following ordered pairs of an inverse function has its one-to-one function indicated in the table below?


f(x)-2-1012
y01234

a. f-1(x) = {(-2,0), (-1,1), (0,2), (1,3), (2, 4)} b. f-1(x) = {(-2,0), (-1,-1), (0,-2), (1,-3), (2,-4)} c. f-1(x) = {(2,0), (1,1), (0,2), (-1,3), (-2, 4)} d. f-1(x) = {(0,-2), (1,-1), (2,0), (3,1), (4,2)}

  1. What is the missing ordered pair in the table below with a f(x) = 2x +9?
f(x)35_____911
y1519_____2731

a. (6,20) b. (7,22) c. (7,23) d. (8,25)

  1. In item number 8, which is the missing inverse ordered pair?
    a. (20, 6)
    b. (22,7)
    c. (23,7)
    d. (25,8)


  2. The illustration shows the one-to-one function and its inverse, which pair has the correct functions?


[chart: line graph of two straight lines, one steep and one shallow, crossing near (2, 2) on axes marked from -6 to 6; the lines are not labeled with equations. Values are not labeled on the chart.]

a.. f (x) = 3x − 4 and f-1(x) = (x + 4)/3 b. f (x) = 3x − 2 and f-1(x) = (x + 2)/3 c. f (x) = 4x − 3 and f-1(x) = (x + 3)/4 d. f (x) = 2x + 3 and f-1(x) = (x − 3)/2

  1. Which term was used to represent the x and y-values of the functions.
    a. Coordinating values
    b. Intersecting values
    c. Table of values
    d. True values


  2. Which is true about f(x) = 5x – 3 and y = (x + 5)/3 ?
    a. They are inverse functions.
    b. They are not inverse functions.
    c. The graphs are parallel to each other.
    d. The graphs intersect at two or more points.


  3. Which of the following graphs best descirbed f (x) = 5x + 3 and y = (x − 3)/5 ?
    a. [illustration: a steep line and a shallow line on a grid, crossing near the x-axis at about (-1, 0)]
    b. [illustration: a steep line and a shallow line on a grid, crossing near the origin]
    c. [illustration: a steep line and a shallow line on a grid, crossing near (3, 3)]
    d. [illustration: a steep line and a shallow line on a grid, crossing near (-1, -2)]


  4. If the function is one-to-one and has x and y-values of (-2, 7), what is its inverse values?
    a. (-2, 7)
    b. (7,-2)
    c. (-7,2)
    d. (7, 2)


  5. If the function is one-to-one and has x and y-values of (5, 0), what is its inverse values?
    a. (5, 0)
    b. (0,-5)
    c. (0, 5)
    d. (-5, 0)


  6. All of the following are used in the representation of inverse function, EXCEPT.
    a. domain
    b. f-1(x)
    c. graph
    d. table of values


  7. Which of the following table of values best represents the correct inverse function of f(x) = 3x + 7?


a.

f-1(x)1-1-3-5-7
y104-2-8-14

b.

f-1(x)-2-1012
y1471013

c.

f-1(x)1471013
y-2-1012

d.

f-1(x)104-2-8-14
y1471013
Additional Activities

Show the inverse function and construct a table of values for each of the following function.

  1. f(x) = (x + 7)/3
  2. f(x) = (x − 2)/5

Answer Key

What I Know
  1. A
  2. D
  3. D
  4. B
  5. D
  6. D
  7. B
  8. A
  9. C
  10. A
  11. A
  12. C
  13. C
  14. C
  15. B
What’s More

[transcriber’s note: this page’s answer boxes are printed upside down; the content below is transcribed in upright reading order.]

Activity 12.1
  1. f(x) = x + 2
f(x)-2-1012
y01234
  1. g(x) = 12x − 1
f(x)-2-1012
y-25-13-11123
  1. h(x) = −x/4
f(x)-2-1012
y1/21/401/41/2

[transcriber’s note: the minus signs on the negative values of item 3 are not clearly legible in the rendered page.]

  1. f(x) = x
f(x)-2-1012
y-2-1012
  1. g(x) = (3x + 5)/8
f(x)-2-1012
y-1/81/45/8111/8
Additional Activities
  1. f(x) = (x + 7)/3
f(x)-4-1258
y12345
f-1(x)12345
y-4-1258

The graph of f(x) = (x + 7)/3 and f-1(x) = 3x − 7

[illustration: two straight lines, one steep and one shallow, drawn as mirror images across the line y = x on a coordinate grid]

  1. f(x) = (x − 2)/5
f(x)-3271217
y-10123
f-1(x)-10123
y-3271217

The graph of f(x) = (x − 2)/5 and f-1(x) = 5x + 2

[illustration: two straight lines, one steep and one shallow, drawn as mirror images across the line y = x on a coordinate grid]

[transcriber’s note: the table rows in item 1 and item 2 of Additional Activities are printed in the rotated answer boxes; they are transcribed in upright reading order.]

Answer Key

What I Can Do
Solution

[transcriber’s note: this page is printed upside down; the text below is transcribed in upright reading order. The fractions are read from the rotated glyphs and are checked against the linear equation in the solution.]

A. Since f is a linear function of x, the temperature in degrees Celsius, we can write f(x) = ax + b. We are given that zero degrees Celsius converts to 32 degrees Fahrenheit so f(0) = b = 32.

In order to find the slope, a, we can use the second piece of data given, namely that 100 degrees Celsius converts to 212 degrees Fahrenheit: 212 = f(100) = a(100) + 32.

Solving for a gives a = 9/5. So to convert the temperature in degrees Celsius to degrees Fahrenheit, the appropriate linear function is f(x) = (9/5)x + 32.

B. The function f multiplies the input, x, by 9/5 and then adds 32. Let’s call the inverse function g. Then an equation describing g could first subtract 32 from its input and then divide by 9/5. Dividing by 9/5 is the same as multiplying by 5/9, so we find g(x) = (5/9)(x − 32).

The function g takes as inputs the temperature in degrees Fahrenheit and gives as output the corresponding temperature in degrees Celsius.

C. If there is a temperature x which is the same in degrees Celsius and in degrees Fahrenheit then we would have f(x) = x. If we solve the equation (9/5)x + 32 = x for x, we find that x = −40. So −40 is the temperature which registers the same on the Fahrenheit and Celsius scales. For temperatures above −40, the temperature in degrees Fahrenheit will be greater than the corresponding temperature in degrees Celsius while for temperatures below −40, the temperature in degrees Fahrenheit is less than the corresponding temperature in degrees Celsius.

[transcriber’s note: this page is printed upside down; the transcription follows the content in reading order]

What’s More
Activity 12.2

[chart: line graph; Activity 12.2, item 1. Values are not labeled on the chart.]

[chart: line graph; Activity 12.2, item 2. Values are not labeled on the chart.]

[chart: line graph; Activity 12.2, item 3. Values are not labeled on the chart.]

[chart: line graph; Activity 12.2, item 4. Values are not labeled on the chart.]

[chart: line graph; Activity 12.2, item 5. Values are not labeled on the chart.]

[chart: line graph; Activity 12.2, item 6. Values are not labeled on the chart.]

Assessment

  1. c
  2. b
  3. a
  4. d
  5. d
  6. c
  7. c
  8. a
  9. c
  10. b
  11. a
  12. b
  13. c
  14. a
  15. b

References

Dimasuay, Lynie, et. al. 2016. General Mathematics. Philippines: C & E Publishing, Inc.

Verzosa, Debbie Marie, et.al. 2016. General Mathematics: Learner’s Material, First Edition. Philippines: Lexicon Press Inc.

For inquiries or feedback, please write or call:

Department of Education – Bureau of Learning Resources (DepEd-BLR)

Ground Floor, Bonifacio Bldg., DepEd Complex Meralco Avenue, Pasig City, Philippines 1600

Telefax: (632) 8634-1072; 8634-1054; 8631-4985

Email Address: blr.lrqad@deped.gov.ph * blr.lrpd@deped.gov.ph

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